A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes?
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A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes?
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- In a certain plant, the dominant form of gene P codes for purple flowers while the recessive form results in pink flowers. The dominant form of another gene, A, activates the transcription of P, while the recessive form prevents the transcription of P and results in white flowers. A doubly-homozygous purple-flowered plant was crossed with a doubly-homozygous recessive white-flowered plant. The F1 progeny were then self-crossed to generate the F2 generation. Determine the ratios of genotypes and phenotypes for each generation.A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes? A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes? a. 1/8 b. 1/16 c.1/2 d. 3/16 e. 1/3 f. 3/4 g. 15/16 h. 2/3 i. 1/4It is assumed that in Drosophila the following genotypes produce phenotypes. َA- B- = Red color A- bb = Plum color aa B- = Magenta color aa bb = White color The third latent genotype, cc, kills homozygous Plums, but has no effect on other genotypes. Also, genotype C- does not produce a large phenotype. If first-generation Drosophilas are heterozygous for all of these genes and interbreed, what phenotypic ratios are expected in society?
- A mutation of Drosophila has a wing condition known as beaded. When a beaded fly was crossed with a pure-line normal fly, 53 beaded and 47 normal F1 's were produced. When two of the F, beaded flies were mated, 67 beaded and 33 normal F2's were produced. Explain the genetics of the beaded trait and give the genotypes of all P and F1 generation flies.In Drosophila, a cross was made between females and wild-type males. The female parents expressed the three X-linked recessive traits miniature wing (m), ebony body (e) and cinnabar eye (c). In the F1, all females were wild type, while all males expressed all three mutant traits. The cross was carried to the F2 generation, and 1500 offspring were produced. 412 403 211 Miniature wing, ebony body, cinnabar eye Wild type Ebony body, cinnabar eye Miniature wing Miniature wing, cinnabar eye Ebony body Miniature wing, ebony body Cinnabar eye 224 103 96 23 28 (i) Using proper nomenclature, determine the genotypes of the females and males in generation P and F1. (ii) What is the correct order of the genes? (iii) Construct a genetic map showing the correct order and distances between these genes.In Drosophila melanogaster, red eyes are dominant over white and the variation for this characteristic is on the X chromosome. Vestigial wings (v) are recessive to normal (V) for an autosomal gene. Predict the appearance of offspring of the following crosses: XW/Xw V/v×Xw/Y v/v, Xw/Xw V/v × XW/Y V/v.
- In Drosophila melanogaster, red eyes are dominant over white and the variation for this characteristic is on the X chromosome. Vestigial wings (v) are recessive to normal (V) for an autosomal gene. Predict the appearance of offspring of the following crosses: XW/XwV/v×Xw/Y v/v, Xw/XwV/v×XW/Y V/v.In Drosophila, a female fly is heterozygous for three mutations, Bareyes (B), miniature wings (m), and ebony body (e). Note that Bar isa dominant mutation. The fly is crossed to a male with normal eyes,miniature wings, and ebony body. The results of the cross are asfollows.111 miniature29 wild type117 Bar26 Bar, mimatue101 Bar, ebony31 Bar, miniature, ebony35 ebony115 miniature, ebonyInterpret the results of this cross. If you conclude that linkage isinvolved between any of the genes, determine that map distance(sbetween them.In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cM
- In fruit flies, the autosomal recessive mutation pr causes brown eyes whereas the cn mutation causes bright-red eyes (again autosomal recessive). When both mutations are homozygous in the individual (double mutant; pr-cn combination), it causes orange eyes. Wild-type flies have red eyes. It is known that these genes are found on the same chromosome. Scenario: A female who has wild-type eyes is crossed to an orange eyed male. Their progeny have the following distribution of eye colors: wild-type 23 brown 220 bright-red 230 orange 27 Total 500 What is the genotype of the mother of these progeny? O pr-cn/pr*-cn* O pr*-cn/pr*-cn O pr*-cn/pr-cn* O pr-cn*/pr-cn* O pr-cn/pr-cnA Drosophila strain with two mutated phenotypes was crossed with a wild-type Drosophila strain. The wild-type phenotypes were present in all of the F1 flies. The F1 flies were bred with one another. The F2 generation, on the other hand, did not have the predicted 9:3:3:1 phenotypic ratio. Explain why these outcomes occurred.Two different strains of Drosophila, strain A and strain B, each has a recessive mutation that results in abnormally bright red eye color. (Wild type flies have brownish red eye color). When a homozygous strain A fly is crossed with a homozygous B fly, all of the progeny have the dominant wild type eye color. The wild type-eyed progeny were allowed to breed among themselves to produce the F2 generation. The F2 generation consisted of 92 wild type and 74 bright red-eyed flies. Write the genotype(s) of the flies in each generation. Use a low dash (e.g. A_ B_) to indicate genotypes that could be either homozygous or heterozygous) a) parental strain A b) parental strain B c) wild type progeny (F1) d) wild type F2 e) bright-eyed F2