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A ratio of exactly 2:1 in the F2 generation, is indicative of:
a. |
epistasis - 3 genes |
|
b. |
incomplete dominance |
|
c. |
linkage |
|
d. |
epistasis -2 genes |
|
e. |
lethality |
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- Refer to question 5. Assuming complete dominance, the F2 generation will show a phenotypic ratio of ________. a. 3:1 b. 9:1 c. 1:2:1 d. 9:3:3:1 Question No. 5 5. The offspring of the cross AA aa are ________. a. all AA b. all aa c. all Aa d. half are AA and half are aaRefer to question 4. Assuming complete dominance, the F2 generation will show a phenotypic ratio of _______. a.3:1 b.9:1 c. 1:2:1 d. 9:3:3:1Match each type of gene interaction with the F2 ratio. Choose from the letters a. 12:3:1 b. 9:7 c. 15:1 d. 9:6:1 e. 9:3:3:1 f. 13:3 g. 9:3:4 1. Dominant epistasis 2. Dominant suppression epistasis 3. Duplicate Dominant Epistasis
- 1. Hemophilia is due to a sex-linked gene. It is recessive and found on the X chromosome. A woman who is a carrier for hemophilia marries a normal man. What will be the possible phenotypes of their children? Use a punnet square. 2. A phenotypically normal man, who has a hemophiliac brother, marries a normal woman, who is not a carrier. What is the probability that any of their children will be hemophiliac? Use a punnet square. 3. Color-blindness is an X-linked, recessive trait. If a normal-sighted woman, whose father was color-blind, marries a colorblind man, what is the probability that they will have a son who is color-blind? Use a punnet square. 4. A man and woman, both of normal vision, have: 1) a color-blind son (#1) who has a daughter of normal vision 2) a daughter (#1) of normal vision who has one color-blind son and one normal vision son 3) another daughter (#2) of normal vision who has five sons, all with normal vision What are the probable genotypes of the…Which of the following terms may be used to describe a disease thathas multiple phenotypes?a. multifactorial d. sex-linkedb. codominance e. pleiotropyc. incomplete dominanceA. Color-blindness is a recessive, sex-linked disorder in humans. A color- blind man has a child with a woman who is a carrier of the disorder. KEY: X= normal vision XC = color-blindness 2. Illustrate using a Punnett square the probability of having children who will have normal vision and children who will be color-blind. Guide Questions: a. What is the genotype of the male?. b. What is the genotype of the female? c. What is the chance that the child will be color-blind? d. What is the chance that a daughter will be color-blind? e. What is the chance that a son will be color-blind?
- Finally, draw out a Punnett square to help you consider the cross between these possible gametes. Sex-Linked1 := Homework • Unanswered What are the possible genotypes of the offspring shown in your Punnett square? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. XBxb and xbY a b XBXB and xbY Neither of these answers is correct Unanswered • 1 attempt left Submit Sex-Linked2 Homework • Unanswered What are the possible phenotypes of the offspring? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a Females with normal color vision and males who are colorblind Females who are colorblind and males who have normal color visionIn Wookies, chocolate (brown) hair (C) is dominant over black hair (c), long hair (L) is dominant over short hair (I), and yellow eyes (Y) is dominant over grey eyes (y). List all the different possible gametes that can be produced by each of the individuals below. A. CCIIYY B. CcLlyy C. CCLIYY D. ccLlyy E. CCLIYYIV. Other dihybrid cross Gene symbols v vestigial wing size V normal wing size s sepia eye color S red eye color The parents were vestigial, red eyed color female and normal wing size, sepia eyed color male Diagram of P1 cross: You are crossing F1s. Diagram of F1 cross: Give expected F2 phenotypic ratio: Give expected F2 genotypic ratio:
- 2.) (6) Assume that brown eyes are dominant = B, blue eyes are recessive = b. My first wife has blues eyes. I know I am homozygous dominant a. What is her genotype? b. What are her possible gamete genotypes? c. What is my genotype? d. What are my possible gamete genotypes? What genotype(s) do you expect of our offspring? Show your work (Punnett square is a good idea). e.. Assuming no involvement of the Bombay phenotype(in case you’ve already read ahead to Section 3.2):a. If a girl has blood type O, what could be the genotypes and corresponding phenotypes of her parents?b. If a girl has blood type B and her mother has bloodtype A, what genotype(s) and correspondingphenotype(s) could the other parent have?c. If a girl has blood type AB and her mother is alsoAB, what are the genotype(s) and correspondingphenotype(s) of any male who could not be thegirl’s father?Based on this karyotype, what is the probability that any one of this women's children would would also be carriers for Down's Syndrome? a 100% or 1/1 b 50% or 1/2 c 25% or 1/4 d 10% or 1/10 e None would be carriers