A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes σ is 1.5 minutes and that the population of times is normally distributed. 7 12 10 11 11 10 10 8 9 8 8 9 10 10 6 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (enter your response here,enter your response here). (Round to one decimal place as needed.)
A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes σ is 1.5 minutes and that the population of times is normally distributed. 7 12 10 11 11 10 10 8 9 8 8 9 10 10 6 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (enter your response here,enter your response here). (Round to one decimal place as needed.)
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A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes
σ
is
1.5
minutes and that the population of times is normally distributed.
7
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12
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10
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11
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11
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10
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10
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8
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9
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8
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8
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9
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10
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10
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6
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Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
The 90% confidence interval is
(enter your response here,enter your response here).
(Round to one decimal place as needed.)Expert Solution
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