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- 2. You walk 30 m South and heads 30 m East. What is your resultant displacement? 2 An cirplane fios due porth ot 1 50 km /hA football player runs from his own goal line to the opposing teams goal line, returning to the fifty-yard line, all in 18.0 s. Calculate (a) his average speed, and (b) the magnitude of his average velocity. (Sec Section 2.2)A brick was dropped from rest from a height of 91.4 m. How long does it take the brick to reach the ground (in seconds) ? note: Use acceleration due to gravity, g = 9.81 m/s?. Select one: Оa. 182.8000 Ob. 4.3167 Ос. 42.3470 Od. 3.0524
- GCDX目 目|目|XE ト Da |目 目ト C/MİMZNZQOMJAZMTY4/a/Mjc5Nzk2NjcwNjcw/details 9. Raul pogo sticks from his locker to his science class. He travels 8 m east then 8 m west back to his locker. What distance did he cover? What was his displacement? 10. Oliver buys a new Seadoo. He goes 12 km north from the beach. He jumps wakes for 6 km to the east. What distance did he cover? What was his displacement? Page 2A ball dropped from a height of 30 cm, takes 0.6067 s to reach the ground. What is the acceleration due to gravity (g) at that place in S.I. units ? Select one: O a. 163 O b. 1.63 Oc. 9.8 O d. 0.988 The time of fall (t) of a free falling object is directly proportional to the height (h)1110. In Fig. P-1109, a ball thrown down the incline strikes it at a distance s 254.5 It. If the ball rises to a maximum height h 64.4 ft above the point of release, compute its initial velocity vo and inclination 6. Ans. v. = 80.5 ft per see; 0= 53.1° FIG. P-1109 and P-1110.
- IV. A stone dropped from a cliff hits the ground 3.00 slater. Assuming the acceleration due to gravity is 9.81m/s2 , finda. the velocity of the stone the instant before it hitsthe groundb. the displacement experienced by the stone init’s fall1つ7 3. An object undergoes motion in 2 dimensions under a constant acceleration of "-2.50 m/s at an angle of 50.0° with respect to the + x direction. It also has an initial velocity of vi = 7.00 m/s at an angle of 10,0° The object begins at the coordinates (0, 0). a) What are the coordinates of the object at t = 7.00 s? Want Cx, y) at t =?4 4tzテメ0チ=XT vse this Con Vxi = \V;l cos v +ハ Ay=lalsin Ga b) What is its total velocity vector of the object as a magnitude and direction at t = 7.00 s? a) Ov= Ton10. When throwing a softball directly upward from a height of 4 ft with an initial velocity of 25 ft/scc, the height of the softball in feet after t seconds is given by y(t) ground). 16t2 +25t + 4 (until the ball hits the А. Find the velocity 1 second after the softball is thrown (include the units). Is the softball going upward or downward 1 second after В. being thrown?
- 91 ll alll ? ۱۰:۰۸ ص v(m/s) t(s) D O Q7:A person is at building-top (50m high). Stone fells down from his hand to reach ground. (A) Calculate stone velocity when hits ground? (B) Time is taken stone to hit ground.Note: Support the solution .with diagram and marking إضافة ملف إرسال رجوع عدم إرسال كلمات المرور عبر نماذج Go ogle مطلقا۔ لم يتم إنشاء هذا المحتوى ولا اعتماده من قبل Go ogle. الإبلاغ عن إساءة الاستخدام - شروط الخدمة - سياسة الخصوصية Google zilaiMy question isn't how to solve the problem exactly. In fact, it's already been solved on this website. My question is about the acceleration. When I solve this problem myself, first I calculate the velocity by dividing 100m by 53s. I get 1.89m/s. Then I use that to find the acceleration using the equation vf = vi + at. That's 1.89/53 = 0.036m/s^2. That's not correct. The correct way to find the acceleration is to us the equation d = 1/2 at^2 and solve that way without taking the intermediate step of finding the velocity. Doing it that way, the acceleration is 0.0712m/s^2. My question is why you get a different result doing it the first way than you get doing it the second way.Lately, Jason has been taking drivers' ed so that he can get his license. However, he's also been taking physics, and so he wonders what his acceleration is, when he drives on a circular path in an empty parking lot near Peachtree Mall with diameter 78.0 m, if he is driving at a constant speed of 23.0 m/s. What is his acceleration? O 66.1 m/s² 13.6 m/s2 O 0.590 m/s² O 1.70 m/s² O 0 m/s²