A poll of 2,096 randomly selected adults showed that 91% of them own cell phones. The technology display below results from a test of the claim that 95% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p=0.95 vs p≠0.95 Sample X N Sample p 95% CI Z-Value P-Value 1 1906 2,096 0.909351 (0.893198,0.925505) −8.54 0.000 Question content area bottom Part 1 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Your answer is correct. Left-tailed test Right tailed test Part 2 b. What is the test statistic? The test statistic is negative 8.54−8.54. (Round to two decimal places as needed.) Part 3 c. What is the P-value? The P-value is 0.0000.000. (Round to three decimal places as needed.) Part 4 d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. A.Upper H 0 : p greater than 0.95 H0: p>0.95 B.Upper H 0 : p not equals 0.95 H0: p≠0.95 C.Upper H 0 : p less than 0.95 H0: p<0.95 D.Upper H 0 : p equals 0.95 H0: p=0.95 Your answer is correct. Part 5 Choose the correct answer below. A. Reject the null hypothesis because the P-value is greater than the significance level, α. B. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α.
A poll of 2,096 randomly selected adults showed that 91% of them own cell phones. The technology display below results from a test of the claim that 95% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p=0.95 vs p≠0.95 Sample X N Sample p 95% CI Z-Value P-Value 1 1906 2,096 0.909351 (0.893198,0.925505) −8.54 0.000 Question content area bottom Part 1 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Your answer is correct. Left-tailed test Right tailed test Part 2 b. What is the test statistic? The test statistic is negative 8.54−8.54. (Round to two decimal places as needed.) Part 3 c. What is the P-value? The P-value is 0.0000.000. (Round to three decimal places as needed.) Part 4 d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. A.Upper H 0 : p greater than 0.95 H0: p>0.95 B.Upper H 0 : p not equals 0.95 H0: p≠0.95 C.Upper H 0 : p less than 0.95 H0: p<0.95 D.Upper H 0 : p equals 0.95 H0: p=0.95 Your answer is correct. Part 5 Choose the correct answer below. A. Reject the null hypothesis because the P-value is greater than the significance level, α. B. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
Related questions
Question
A poll of
normal distribution as an approximation to the binomial distribution, and assume a
2,096
randomly selected adults showed that
91%
of them own cell phones. The technology display below results from a test of the claim that
95%
of adults own cell phones. Use the 0.01
significance level to complete parts (a) through (e).
Test of
p=0.95
vs
p≠0.95
|
||||||
Sample
|
X
|
N
|
Sample p
|
95% CI
|
Z-Value
|
P-Value
|
---|---|---|---|---|---|---|
1
|
1906
|
2,096
|
0.909351
|
(0.893198,0.925505)
|
−8.54
|
0.000
|
Question content area bottom
Part 1
a. Is the test two-tailed, left-tailed, or right-tailed?
Two-tailed test
Left-tailed test
Right tailed test
Part 2
b. What is the test statistic?
The test statistic is
negative 8.54−8.54.
(Round to two decimal places as needed.)
Part 3
c. What is the P-value?
The P-value is
0.0000.000.
(Round to three decimal places as needed.)
Part 4
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
H0: p>0.95
H0: p≠0.95
H0: p<0.95
H0: p=0.95
Part 5
Choose the correct answer below.
Reject
the null hypothesis because the P-value is
greater than
the significance level,
α.
Reject
the null hypothesis because the P-value is
less than or equal to
the significance level,
α.
Fail to reject
the null hypothesis because the P-value is
greater than
the significance level,
α.
Fail to reject
the null hypothesis because the P-value is
less than or equal to
the significance level,
α.
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