A point charge, q = -5.00 nC, and m = 2.00 x 10-14 kg, is shot vertically upward with an initial speed of 2.00 x 103 m/s from a thin, infinite, planar sheet of uniform charge with surface charge density of σ = +4.00 (nC)/m^2. To what vertical elevation will q rise above the sheet of charge? Neglect gravity.   a. 2.43 cm   b. 0.635 cm   c. 1.20 cm   d. 3.54 cm   e. 1.97 cm

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Chapter6: Gauss's Law
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Problem 68P: Two parallel conducting plates, each of cross-sectional area 400 cm2, are 2.0 cm apart and...
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A point charge, q = -5.00 nC, and m = 2.00 x 10-14 kg, is shot vertically upward with an initial speed of 2.00 x 103 m/s from a thin, infinite, planar sheet of uniform charge with surface charge density of σ = +4.00 (nC)/m^2. To what vertical elevation will q rise above the sheet of charge? Neglect gravity.

  a.

2.43 cm

  b.

0.635 cm

  c.

1.20 cm

  d.

3.54 cm

  e.

1.97 cm

A point charge, q = -5.00 nC, and m = 2.00 x 10-14 kg, is shot vertically upward with an initial speed of 2.00 x 10° m/s from a thin, infinite, planar sheet
of uniform charge with surface charge density of o = +4.00
nC
To what vertical elevation will q rise above the sheet of charge? Neglect gravity.
m2
V¡ = 3.00 x 105 m
О а.2.43 cт
O b.0.635 cm
О с. 1.20 cm
O d. 3.54 cm
O e. 1.97 cm
Transcribed Image Text:A point charge, q = -5.00 nC, and m = 2.00 x 10-14 kg, is shot vertically upward with an initial speed of 2.00 x 10° m/s from a thin, infinite, planar sheet of uniform charge with surface charge density of o = +4.00 nC To what vertical elevation will q rise above the sheet of charge? Neglect gravity. m2 V¡ = 3.00 x 105 m О а.2.43 cт O b.0.635 cm О с. 1.20 cm O d. 3.54 cm O e. 1.97 cm
Expert Solution
Step 1

Part (1):

Given:

The charge on the particle is -5 nC.

The mass of the particle is 2x10-14 kg.

The initial velocity of the particle is 2x103 m/s vertically upward.

The surface charge density of the sheet is +4 nC/m2.

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