A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-g bullet moving with a speed of 1.50 x 10³ m/s. What must the baseball'sspeed be if the pitcher's claim is valid?Answer:____m/s

Given: Mass of baseball mbaseball=0.145 kg, Mass of bullet mbullet=3 g=3×10-3 kg, Speed of bullet…

Answered: A pitcher claims he can throw a…

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter6: Momentum And Collisions

Section: Chapter Questions

Problem 3P: A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-kg bullet moving...

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Question

A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-g bullet moving with a speed of 1.50 x 10³ m/s. What must the baseball's
speed be if the pitcher's claim is valid?
Answer:____
m/s

Expert Solution

Concept

Given: Mass of baseball $m_{b a s e b a l l} = 0.145 k g$ , Mass of bullet $m_{b u l l e t} = 3 g = 3 \times 10^{- 3} k g$ , Speed of bullet $v_{b u l l e t} = 1.5 \times 10^{3} m / s$ .

Required: Speed of baseball $(v_{b a s e b a l l})$ .

Momentum of an object of mass m moving with speed v is given by, $p = m v$ .

According to the question, $p_{b a s e b a l l} = p_{b u l l e t}$ .

$m_{b a s e b a l l} v_{b a s e b a l l} = m_{b u l l e t} v_{b u l l e t}$

$v_{b a s e b a l l} = \frac{m_{b u l l e t} v_{b u l l e t}}{m_{b a s e b a l l}}$

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