A piece of wire of length 53 is cut into two pieces. One piece is bent into a square and the other is bent into a circle. If the sum of the areas enclosed by each part is a minimum, what is the length of each part?531+ ATo minimize the combined area, the wire should be cut so that a length of(Round to the nearest thousandth as needed.)is used for the circle and a length of531 + Ais used for the square.

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A piece of wire of length 53 is cut into two pieces. One piece is bent into a square and the other is bent into a circle. If the sum of the areas enclosed by each part is a minimum, what is the length of each part? To minimize the combined area, the wire should be cut so that (Round to the nearest thousandth as needed) length of 53x 1+x CLE is used for the circle and a length of 53 1+x is used for the square.

A piece of wire of length 53 is cut into two pieces. One piece is bent into a square and the other is bent into a circle. If the sum of the areas enclosed by each part is a minimum, what is the length of each part? To minimize the combined area, the wire should be cut so that (Round to the nearest thousandth as needed) length of 53x 1+x CLE is used for the circle and a length of 53 1+x is used for the square.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter8: Polynomials

Section8.1: Adding And Subtracting Polynomials

Problem 71PFA

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