A particle which moves in two-dimensional curvilinear motion has coordinates in millimeters which vary with time t in secondsaccording to x = 4.1t² + 3.1 and y = 3.6t3 + 5.3. For time t = 3.2 s, determine the radius of curvature p of the particle path and themagnitudes of the normal and tangential accelerations.Answers: At t = 3.2 s,p=an =at =1619.77.97769.6mmmm/s²mm/s²

Answered: Image /qna-images/answer/86078778-8936-4cc5-b8dc-9bf17a83a80a.jpg

A particle which moves in two-dimensional curvilinear motion has coordinates in millimeters which vary with time t in seconds according to x = 4.1t² + 3.1 and y = 3.6t³ + 5.3. For time t = 3.2 s, determine the radius of curvature p of the particle path and the magnitudes of the normal and tangential accelerations. Answers: At t = 3.2 s, p= an = at = 1619.7 7.977 69.6 mm mm/s² mm/s²

A particle which moves in two-dimensional curvilinear motion has coordinates in millimeters which vary with time t in seconds according to x = 4.1t² + 3.1 and y = 3.6t³ + 5.3. For time t = 3.2 s, determine the radius of curvature p of the particle path and the magnitudes of the normal and tangential accelerations. Answers: At t = 3.2 s, p= an = at = 1619.7 7.977 69.6 mm mm/s² mm/s²

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 3OQ: Figure OQ3.3 shows a birds-eye view of a car going around a highway curve. As the car moves from...

See similar textbooks

Similar questions

Figure OQ3.3 shows a birds-eye view of a car going around a highway curve. As the car moves from point 1 to point 2, its speed doubles. Which of the vectors (a) through (e) shows the direction of the cars average acceleration between these two points?
A particle moving in the x-y plane has a position vector given by r- 1.67t2i+1.44t³j, where r is in inches and t is in seconds. Calculate the radius of curvature p of the path for the position of the particle when t- 1.9 sec. Sketch the velocity v and the curvature of the path for this particular instant. Answer:p-i in.
A particle moving in the x-y plane has a position vector given by r = 0.81t²i + 0.74t³j, where r is in inches and t is in seconds. Calculate the radius of curvature p of the path for the position of the particle when t = 2.1 sec. Sketch the velocity v and the curvature of the path for this particular instant. Answer: p= i in.
A particle moving in the x-y plane has a position vector given by r = 1.12t²i + 1.30t³j, where r is in inches and t is in seconds. Calculate the radius of curvature p of the path for the position of the particle when t = 2.5 sec. Sketch the velocity v and the curvature of the path for this particular instant. Answer: p= i eTextbook and Media in.
A particle moves ccw on a circular path of 400 ft radius. It starts from a fixed point which is horizontally to the right of the center of the path and moves so that s = 10t2 + 20t where s is the arc distance in ft and t is the time in sec. Compute the x and y components of the acceleration at the end of 3 seconds.
A particle which moves in two-dimensional curvilinear motion has coordinates in millimeters which vary with time t in seconds according to x = 4.1t² + 3.1 and y = 3.6t3 + 5.3. For time t = 3.2 s, determine the radius of curvature p of the particle path and the magnitudes of the normal and tangential accelerations. Answers: At t = 3.2 s, p= an at = mm mm/s² mm/s²
Your answer is partially correct. A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.90 m, 3.70 m) with a velocity of -2.40 î m/s and an acceleration of +11.9 m/s². What are the (a) x and (b) y coordinates of the center of the circular path? (a) Number i 4.41 (b) Number i 3.70 Unit Unit m m
A particle moves on a 4-in radius circular path. The distance, measured along the path, is given by s = 8t^3 in. What is the magnitude of the total acceleration after the particle has traveled around the circular path once?The answer is 667 in/s^2
A particles position and path at any given time is given by y = -2t2+10t (m) and x = t2 +1 (m) and t is in seconds. Determine the velocity, acceleration, and radius of curvature of the particle when t=1 second. Then sketch the velocity and acceleration vectors as well as the direction of the radius of curvature with appropriate n-t coordinates.
A particle moves in uniform circular motion in the xy plane. At one time, the particle is moving past the coordinates (6m, 6m) with a speed of -10?̂ m/s and an acceleration of 16.5?̂ m/s2. What are the x and y coordinates at the center of the particle's circular path? ( please answer in detail )
A particle is moving along a circular path having a radius of 4 in. such that its position as a function of time is given by theta = cos 2t, where theta is in radians and t is in seconds. Determine the magnitude of the acceleration of the particle when theta = 30.
A particle travels clockwise around a circular path as shown below. The speed of the particle is given as a function of position s, such that v(s) = (s^2 ) m⁄sec where position is measured in meters. The radius of the circle is 1 m. What is the magnitude of the acceleration of the particle at the position s = 1 m?