A particle moves so that its position (in meters) as a function of time (in seconds) is r = î + 5t2 j + 5t k. (Use the following as necessary: t.) (a) Write an expression for its velocity as a function of time. V = m/s (b) Write an expression for its acceleration as a function of time. a = m/s2

A particle moves so that its position (in meters) as a function of time (in seconds) is r = î + 5t2 j + 5t k. (Use the following as necessary: t.) (a) Write an expression for its velocity as a function of time. V = m/s (b) Write an expression for its acceleration as a function of time. a = m/s2

Name: A particle moves so that its position (in meters) as a function of ti
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: A particle moves so that its position (in meters) as a function of time (in seconds) is r = î + 5t2 j + 5t k. (Use the following as necessary: t.)(a) Write an expression for its velocity as a function of time.V =m/s(b) Write an expression for its ac

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Please answer the following question(s): 1. The speed of a boat in still water is vá. A river flows with a speed of v₁. The boat travels distance of 19 miles downstream in a river in 1 hour. However, the return journey takes 2 hours. Calculate the vand v₁. Hint: Velocity=displacement/time. Displacement can be positive of neagtive depending on the direction. You will first need to set up the equations by taking into account the resultant velocity of the boat in flowing water. Consider the direction the river is flowing to be positive. Set up two equations, one for the downstream journey and one for the upstream journey, in terms of "v" and "v": Do v" and "v, add or substract downstream to give the resultant downstream velocity? Do v" and "v, add or substract upstream togive the resultant upstream velocity? Use the upstream direction as negative. The resultant upstream velocity should be negative. vb vb Downstream positive Vr Upstream negative Vr
A particle moves so that its position (in meters) as a function of time (in seconds) is r = î + 2t² j+ 2tk. (Use the following as necessary: t.) (a) Write an expression for its velocity as a function of time. v(t) = m/s (b) Write an expression for its acceleration as a function of time. d(t) = m/s2 Submit Answer
My question isn't how to solve the problem exactly. In fact, it's already been solved on this website. My question is about the acceleration. When I solve this problem myself, first I calculate the velocity by dividing 100m by 53s. I get 1.89m/s. Then I use that to find the acceleration using the equation vf = vi + at. That's 1.89/53 = 0.036m/s^2. That's not correct. The correct way to find the acceleration is to us the equation d = 1/2 at^2 and solve that way without taking the intermediate step of finding the velocity. Doing it that way, the acceleration is 0.0712m/s^2. My question is why you get a different result doing it the first way than you get doing it the second way.
Consider an object moving along a line with the given velocity v. Assume time t is measured in secondsand velocities have units of m/s.a. Determine when the motion is in the positive direction and when it is in the negative direction.b. Find the displacement over the given interval.c. Find the distance traveled over the given interval.v(t) = 50e-2t on [0, 4]
a. The position of an object is given by x(t) = A + B*t + C*t³ (yes, those exponents are intentional, this is NOT constant acceleration). Provided that x is measured in meters and t in seconds, what must be the units for the constants A, B, and C. b. Another position function is given by y(t) = D # E*t1 + F*t3/2). What are its velocity, and acceleration functions with time? c. Bonus: choose and declare your values for D, E and F, and make graphs of y(t), vy(t), and a,(t). Don't forget appropriate units at each step.
A person drops a rock from the edge of a cliff that is 1350 ft high. The initial acceleration is a=−32 ft/sec^2. 1. What is the velocity equation? Use t as the variable and v for the velocity. 2. What is the displacement equation? Use t as the variable and s as the displacement. 3.What time did it hit the ground? (Hint: s=0) 4. What was the velocity just before impact?
I don't understand how to do this problem. I tried taking the derivative, but that didn't give me the correct answer. I would really appreciate the help. When a 1984 Alpha Romeo Spider sports car accelerates in the x-direction at the maximum possible rate,its motion during the first 20. seconds is extremely well modeled by the simple equation vx2=(60 m2/s3)t, where t is time in seconds and vx is in m/s. In other words, the squareof teh car's velocity increases linearly with time. What is its acceleration after 3s, assuming that the car starts from rest at t=0 s?
The velocity-time graph that describes the velocity of an object with time is given as in the figure below. if the values of a= 98.5, b=124.6 and c=57, Find the displacement made by the object in the first hour. v(km/h) b. a t(h) 0.5 1.0 1.5 2.0 Select one: A. 118.1 OB. 175.1 OC 398.4 OD. 139.6 OE 142.7 choice
A student witnesses a flash of lightning and then t = 1.5 s later the student hears the associated clap of thunder.Sound travels at 343 m/s in the air. What distance from the student is the lightning strike, in meters? Light travels at 3.0 × 108 m/s in the air. How long, t1, in seconds did it take the light to reach the student's eyes after the lightning strike?
I took 2.28km and converted it to 2280 meters then divided by 3200 and ended up with .71m/s but it keeps saying that its incorrect. Im not sure where I keep messing up. John walks 1.80 kmkm north, then turns right and walks 1.40 kmkm east. His speed is 1.60 m/sm/sduring the entire stroll. What is the magnitude of his displacement, from beginning to end? (2.28) If Jane starts at the same time and place as John, but walks in a straight line to the endpoint of John's stroll, at what speed should she walk if she wants to arrive at the endpoint just when John does?
The prompt is in the image attached. The questions I need help are:a) Evaluate the acceleration at t=1.0 s. Express your answer in m/s^2 in 2 significant figures.b) Evaluate the acceleration at t=11s. Express your answer in m/s^2 in 2 significant figures.Thank you!
A ball is tossed vertically from the top of a building that is 96 stories tall (approximately 864 ft) with an initial velocity of 30 ft/sec. The initial acceleration is given by a=−32 ft/sec2. 1. Write the velocity equation with t as the variable and v as velocity. 2. Write the displacement equation with t as the variable and s as the displacement. 3. Find the velocity at 2 seconds. ______ ft/s 4. Find the height above the ground at 2 seconds. ______ft