A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.90 s, it is at point (4.60 m, 5.00 m) with velocity (2.00 m/s)ĵ and acceleration in the positive x direction. At time t2 = 13.6 s, it has velocity (–2.00 m/s)î and acceleration in the positive y direction. What are the x and y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.

College Algebra
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ISBN:9781337282291
Author:Ron Larson
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Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.90 s, it is at point (4.60 m, 5.00 m) with velocity (2.00 m/s)ĵ and acceleration in the positive x direction. At time t2 = 13.6 s, it has velocity (–2.00 m/s)î and acceleration in the positive y direction. What are the x and y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.

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Given Motion is a circular motion. r = radius of the circlea = x-cordinate of the centreb = y-cordinate of the centreEquation of the circlex-a2 + y-b2 = r2Also given:At A, t1 =4.90sposition of the particle = 4.60, 5.00 velocity,Vx = 0 m/s and Vy =  2.00 m/s  Acceleration, ax > 0 m/s2, ay = 0 m/s2At B,  t2 =13.6sposition of the particle = x2, y2 velocity,Vx = -2 m/s and Vy =  0.00 m/s  Acceleration, ax = 0 m/s2, ay > 0 m/s2Given: Velocity remains constant along the path

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