A particle is moving along a path y = f(x) as shown. The horizontal position of the particle is linear with time, i.e., x = 4t where t is in seconds. The vertical velocity, Vy of the particle is linear in x and is equal to 16 m/s at x = 10m. Determine the following: i) the path, y = f(x), and ii) velocity and acceleration of the particle when t = 2.5s. y= $ (x) X (m) jom
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