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- A new asteroid is discovered to have an orbital period of 4.685 yrs. Calculate the average orbital radius in kilometers.
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- An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 2.512.51 times Earth's. What is the asteroid's orbital period ?T, its "year," in terms of Earth years?Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)In a distant star system there are many inhabitable planets. One of these planets is named Qomar. Qomar is 3.2 AU's from its star and takes 6.5 Earth years to go around its star once. There is another planet in the same star system called Ferenginar. Ferenginar is 0.9 AUs from the star. What is the length of a Ferengi year (on Ferenginar) in terms of Earth years?
- At an altitude of 160 km above the earth's surface, a 3-kg mass is pushed vertically upward with a velocity of 16,000 km/h. Using the radius of the earth equal to 6357 km, calculate the maximum distance from the earth's surface reached by the mass. Present your answer in km using 4 significant figures.Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1 A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x 10^30 kg , use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). c) Convert the period in part b) to years(Round to the nearest tenth).What is the gravity of Mars, if the mass of the planet is 6.39x1023kg and the radius of the planet is 3397.2 km? What problems would there be on a mission to Mars?
- (a) Jupiter's third-largest natural satellite, Io, follows an orbit with a semimajor axis of 422,000 km (4.22 ✕ 105 km) and a period of 1.77 Earth days (PIo = 1.77 d). To use Kepler's Third Law, we first must convert Io's orbital semimajor axis to astronomical units. One AU equals 150 million km (1 AU = 1.50 ✕ 108 km). Convert Io's a value to AU and record the result. aIo = AU (b) One Earth year is about 365 days. Convert Io's orbital period to Earth years and record the result. PIo = yr (c) Use the Kepler's Third Law Calculator to calculate Jupiter's mass in solar units. Record the result. MJup(Io) = MSun (d) Based on this result, Jupiter's mass is about that of the Sun. Jupiter has a similar fraction of the Sun's volume. The two objects therefore have rather similar density! In fact, Jupiter has a fairly similar composition as well: most of its mass is in the form of hydrogen and helium.An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 1.870 times Earth's. What is the asteroid's orbital period, in terms of Earth years?A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radius of 12 AU and takes 117 days to orbit the star. Determine the mass of the star. State your answer with appropriate mks units. [NOTE: AU ..stands.for...astronomical unit". It is the average distance between Earth & the Sun. 1 AU≈ 1.496 x 1011 m.] Enter a number with units. I be quite large and your calculator will display the answer as a power of 10. If, as an example, your answer was 8.54 x 1056, you would type "8.54e56" into the answer box (remember to state your units with your answer).]
- According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.82 x 105 km. The Moon orbits the Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month). Calculate the orbital velocity of the Moon in m/s.Observations and trigonometry can be used to determine that Earth's moon has an orbital period of 27.32 days and a mean orbital radius of 384,400 km. Using this information, calculate the mass of the Earth.Astronomical observations of our milky way galaxy indicate that it has a mass of about 8x1011 solar masses. A star orbiting near the galaxy's periphery is 5.6x104 light years from its center. a.) What should be the orbital period (in years) of that star be? b.) If its period is 6.4x107 years instead, what is the mass (in solar masses) of the galaxy? Such calculations are used to imply the existence of "dark matter" in the universe and have indicated, for example, the existence of very massive black holes at the center of some galaxies.