the answer is correct I just need the calculations please A mixture of 50.00 grams propane, C3Hs, and 100.00 grams oxygen, O₂, is combusted. C3H8 - 44.10g/mol and the reaction is C3H8 (g) +50O2(g) → 3CO₂(g) + 4H₂O(g). Select words from thedropdown menus to fill in the blanks in the statement below.is the limiting reactant andOxygenis in excess.✓ 22.42grams ofpropane

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A mixture of 50.00 grams propane, C3H8, and 100.00 grams oxygen, O₂, is combusted. C3H8 - 44.10 g/mol and the reaction is C3H8 (g) +502(g) → 3CO2(g) + 4H₂O(g). Select words from the dropdown menus to fill in the blanks in the statement below. Oxygen is the limiting reactant and is in excess. 22.42 grams of propane

A mixture of 50.00 grams propane, C3H8, and 100.00 grams oxygen, O₂, is combusted. C3H8 - 44.10 g/mol and the reaction is C3H8 (g) +502(g) → 3CO2(g) + 4H₂O(g). Select words from the dropdown menus to fill in the blanks in the statement below. Oxygen is the limiting reactant and is in excess. 22.42 grams of propane

Introductory Chemistry: A Foundation

8th Edition

ISBN:9781285199030

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 19CR

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