A linear network has a current input 4cos (ot + 120°)A and a voltage output 10 cos(@ t+110°) V. What is the value of the impedance? 2.46-0.43j None of the answers 2.5-10j 0.39+0.069j
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- Ererrises: IA platinum oil has a resifance of 3-14k r at go°C and 3.747JV at 100°C.- Fin'd the resistance at o'C ond the kmp -creff. of resifonce af 40°C 2. A pofential difference of r5oV is apphed to a field wnding at 15°C and the currend is SA. What will be the mean fempouafure of the winiding when currend has falen to 3.91A, apphedvrltage being constant Aasume s =p7.5. 3. A cril has a resi fance of 182 when its mean femperature is 20°C and 20v when ik mean femperature s 50°C. Frid is mean femperature rise when ik resotonce is 21JL and the sorrandinig femperature is i5°C. A cril of a relay takes a curre of 0.12 A when it is at the vem insbi o al 4. A jemperature of is'C ond canneckerdacms a oV supply If the minimum operating current of the relay is 0.1 A, colculate the femperature above ohich the relay will fail to operate when connected ti the same supply. Resi tncenfemp.coefficrenf of the cril makria] is o.0043 per °C at 0°C.18 In the circuit shown in the figure below, for what value of C will the current-I be in phase with the sinusoidal source voltage V= sin2t? Vs (1 + j1) Q (a) -F 4 (b) (c) (d) 1F /-H.W 2 An AC circuit includes two sections AB and BC in series. The section AB consists of two branches in parallel. The first of these is formed of resistance of 60 2 in series with a capacitor of 50 mF, while the second consists of a resistance of 60 2 having an inductance of 250 mH. The section BC consists of a resistance of 100 N having an inductance of 300 mH. The frequency of the current is 50 Hz. The voltage across section AB is 500 V. What is the voltage across the section BC?
- The source in the circuit shown is a sinusoidal source. The supply voltages across various elements are marked in the figure. The input voltage is: 3V- ww -14 V-10V moon ItThe impedance of a circuit placed across a 120V, 50 Hz source is (10 +j20). Find the power. O 175 watt O144 watt O200 watt O288 wattPHASE RELATIONSHIP SINUSOIDAL( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).
- An inductive impedance and a resistance is connected in series with a 220V ac source. The power factor of the circuit is 0.94. If the voltage drop in the impedance is the same as the voltage drop across the resistance, find the voltage across the impedance.Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…Consider the following circuit used to provide power for an inductive RL load. The input voltage is Vs-100V and the load has a 50 impedance value. The thyristor is working at a frequency fs = 2 kHz. The discharge current is to be limited to 40A and the required dv/dt is 40V/us. If the value of Cs is equal to 0.14uF, then the snubber losses are equal to: T1 Vs Select one: O a. 3.4W O b. 1.4W 5.4W Od. 7.4W