A IS box Pro ves hori zon tal Ir tion lese sur tace between back and fo,th 64 a two ditterent the box is initially springs pressed against the stronger springs 1orpreuing it 4.0 cm Gnd then is releosed From rest. k= 32 N /cm box k=16 N /cm |la) by how much will the box Compiess the weakersping 6) What is the maximon peed the tox will reach ?

University Physics Volume 1
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ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
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Chapter7: Work And Kinetic Energy
Section: Chapter Questions
Problem 39P: A bungee cord is essentially a very long rubber band that can stretch up to four times its...
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A I.S ka bot moves back and forth
hori zon tal frietionless sor tace between
the box is nitially
pressed agains t the stronger spring lorpieuing
64
a
two ditterent
springs :
it 4.0 cm and then is
released trom rest.
k= 32 N /cm
k=16 N/cm
box m m
la) by how much will the box compiess
the weaker sping
6) What is the maximom jpeed the bot
will reach
Transcribed Image Text:X Exit full screen Press Esc to exit full screen A I.S ka bot moves back and forth hori zon tal frietionless sor tace between the box is nitially pressed agains t the stronger spring lorpieuing 64 a two ditterent springs : it 4.0 cm and then is released trom rest. k= 32 N /cm k=16 N/cm box m m la) by how much will the box compiess the weaker sping 6) What is the maximom jpeed the bot will reach
Expert Solution
Step 1

(a)

By conservation of energy,

Ef=Ei12kx22=12kx12x2=k1k2x1

Here x2 is the compression of the weaker spring, and x1 is the compression of the stronger spring.

Substitute the given values,

x2=32N·cm-116N·cm-14.0cmx2=5.66cm

Thus, the compression of the weaker spring is 5.66cm.

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