a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the memory address of 0 * 2000008 b) In the Peripheral region, if the value in the alias address 0 * 4200 0088 to 0 * 4200 008B was set to 0x00000001, what is the bit # and the address in the peripheral region that wants to set to 1?
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a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the memory address of 0 * 2000008
b) In the Peripheral region, if the value in the alias address 0 * 4200 0088 to 0 * 4200 008B was set to 0x00000001, what is the bit # and the address in the peripheral region that wants to set to 1?
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- 3. The contents of memory location B0007H are FFH and those at BO00AH are O0H. What is the data word stored starting at address B0008H? Is the word aligned or misaligned? And how many cycles are used to transfer this word if (a) BS16' is negated (b) BS16' is asserted?a. Find the address accessed by each of the following instructions. If DS = 0100H, BX= 0120H, DATA = 0140H, and SI = 0050H and real mode operation:1. MOV DATA[SI], ECX2. MOV BL, [ BX+SI]b. Descriptor contains a base address of 00260000H, a limit of 00110H, and G = 1,determine starting and ending locations are addressed by the descriptor for aCore2.Q1- Write a program in assembly language for the 8085 microprocessor to receive 10 bytes of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When you receive each byte of the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception (start bits), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit). The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes The solution must be integrated and include the calculation of the baudrate delay time Of+CD!HID+[00 Yes SIDATA Read SID Start Bit? Wait for Half-Bit Time Set up Bit Counter Wait Bit Time Read SID Save Bit Decrement Bit Counter All Bits Received? Add Bit to Previous Bits Go Back to Get Next Bit Return IMUNI
- Q2- Write a program in assembly language for the 8085 microprocessor to receive one byte of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz . When receive the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception(start bits 1 1 ), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit 0 ). The following flowchart will help you. The solution must be integrated and include the calculation of the baudrate delay timeQ1:/ Show the contents in hexadecimal of registers PC, AR, DR, AC, IR and SC of the basic computer when an instruction at address 021 in the basic computer has I = 1, an operation code of the ADD instruction, and an address part equal to 051. The memory word at address 051 contains 0083. The memory word at address 083 contains B8F2. The memory word at address 038 contains A837 and the content of AC is A937. Give the answer in a table with six columns, one for each register and a row for each timing signal. (All numbers are in hexadecimal) uipors - eaAnswer the question below based on given portion of the memory unit with a word size of 8 bits, and the four 8-bit registers: AR, BR, CR, and DR. (all values are in binary) Address Data b0100001 00001110 p0100010 01011100 00100011 00011001 The four 8-bit registers AR, BR, CR, and DR initially have the following values: AR = 00100011 BR = 00000101 CR = 00101101 DR = 01001011 Fill the missing fields in the memory unit below and determine the 8-bit values in each register after the execution of the following sequence of microoperations. DR <- MJARI, BR <- BR+2 DR <- DR+CR, AR <- AR-2 M[AR] <- DR Address Data p0100001 00100001 b0100010 00100010 00100011 00100011 AR = 00100011 BR = 00000101 CR = 00101101 DR = 01001011
- By assuming that X = 3, and 33 is a two digit number, consider memory storage of a 64-bit word stored at memory word 33 in a byte-addressable memory (a) What is the byte address of memory word 33? (b) What are the byte addresses that memory word 33 spans? (c) Draw the number 0xF1234567890ABCDE stored at word 33 in both big endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.Consider memory storage of a 32-bit word stored at memory word 34 in a byte addressable memory. (a) What is the byte address of memory word 34? (b) What are the byte addresses that memory word 34 spans? (c) Draw the number 0x3F526372 stored at word 342 in both big-endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.Question 4: There is an application that requires the hardware: an Intel 8031, a Program ROM of 8Kx8, a Data ROM of 4Kx8 for look-up tables, TWO Data RAMs of 8Kx8. The memory map of the design should be: Program ROM should start at address 0000μ. Then, the Data ROM should come above the Program ROM. Finally the Data RAMs must go to the top of the memory map. There should be no gaps between the memory addresses of the external ROMs or RAMS. A. Using logic gates, draw the pin connections of the design. Label your diagram fully. B. Calculate the address space of the ROMs and RAMs of your design. C. Show the design's address space on a memory map, starting with 0000μ at the bottom and FFFFH at the top.
- 2. Memory contents (in hexadecimal) are 0005, 0001, 0123 for addresses 000 to 002, then 2002, 1000, 7800, F400 for addresses 80A through 80D. AC starts with value 0F24, PC has the value 80A, and AR has the value 4F5. Starting with time-step T0, describe what happens until the next TO. Make sure to indicate any updated register values as they happen. (Assume R= 0.) Refer to table 5.6 from Mano's textbook. F24 1 ARQUESTION 9 What is the hexadecimal representation of the memory variable location at address 003FBA03H in the Little Endian format from the 32-bit binary quantity represented by 10100111 110111100101101100001100b? Address in hexadecimal format 003FBA00H 003FBA01H 003FBA02H 003FBA03H 003FBA04H Data in hexadecimal format O a. The hexadecimal representation for the variable located at memory address 003FBA03 is A8. Ob. The hexadecimal representation for the variable located at memory address 003FBA03 is A5. OC. The hexadecimal representation for the variable located at memory address 003FBA03 is A3. Od. The hexadecimal representation for the variable located at memory address 003FBA03 is A7.Evaluate the expression: F = (c -a)*d +e-b focusing 1- address through 3-address format. Also explain which addressing mechanisms bears maximum number of instructions and why?