A hollow tubular component is made of Steel having a Young's modulus of 205 GPa and yield strength of 250 MPa. The component has an external diameter of 45 mm and a wall thickness of 3 mm. It has a length of 4 m. A1. The component is subject to a torque of 580 Nm. Calculate the Shear Stress at the external surface
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- The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe.Two sections of steel drill pipe, joined by bolted flange plates at Ä are being tested to assess the adequacy of both the pipes. In the test, the pipe structure is fixed at A, a concentrated torque of 500 kN - m is applied at x = 0.5 m, and uniformly distributed torque intensity t1= 250 kN m/m is applied on pipe BC. Both pipes have the same inner diameter = 200 mm. Pipe AB has thickness tAB=15 mm, while pipe BC has thickness TBC= 12 mm. Find the maximum shear stress and maximum twist of the pipe and their locations along the pipe. Assume G = 75 GPa.Compare the angle of twist 1 for a thin-walled circular tube (see figure) calculated from the approximate theory for thin-walled bars with the angle of twist 2 calculated from the exact theory of torsion for circular bars, Express the ratio 12terms of the non-dimensional ratio ß = r/t. Calculate the ratio of angles of twist for ß = 5, 10, and 20. What conclusion about the accuracy of the approximate theory do you draw from these results?
- A motor driving a solid circular steel shaft with diameter d = 1.5 in, transmits 50 hp to a gear at B, The allowable shear stress in the steel is 6000 psi. Calculate the required speed of rotation (number of revolutions per minute) so that the shear stress in the shaft does not exceed the allowable limit.Section A: General A hollow tubular component is made of Steel having a Young's modulus of 205 GPa and yield strength of 250 MPa. The component has an external diameter of 45 mm and a wall thickness of 3 mm. It has a length of 4 m. A1. The component is subject to a torque of 580 Nm. Calculate the Shear Stress at the external surface A2. The component then has a tensile load applied normal to its cross-section of 38KN. Calculate the resulting longitudinal stress.Bearing stress 4. Please provide proper discussion and illustration also complete solution and clear solution please thank you Determine the length of a square key to be used for a 3.73 kW, 1800 rpm electric motor if the motor shaft diameter is 35 mm and the width of the key is approximately one-fourth of the shaft diameter. The allowable shearing stress on the key is 2.45 MPa
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- 4. What length of a square key is required for a 4-in diameter shaft transmitting 1000 hp at 1000 RPM? The allowable shear and compressive stresses in the key are 15 ksi and 30 ksi, respectively.3) A 10 kN-m torque, T, and a 50 kN axial load, F, are applied to the end of an aluminum 6063 tank containing compressed air under a pressure of 2 MPa. The tank has a 400 mm outer diameter and a 20 mm wall thickness. Aluminum 6063 has a yield strength of 48 MPa. a. Draw and label a stress element for the most stressed point on the tank. Explain why this is the most stressed point. b. Sketch Mohr's circle and find the principal stresses at the most stressed point. Make sure you label your axes! c. Determine whether or not this is a safe loading scenario by considering the max normal stress, max shear stress, and distortion energy. (Hint - calculate the factor of safety for each failure criteria) TQ1 The screw of the shaft straightener exerts a load of 3000Kg. The screw-type is square threaded of outside diameter (7.5cm) and (6mm) pitch. Take the height of the nut (150mm). Determine 1) Force required at the rim of 30cm diameter hand wheel, assuming a coefficient of friction is 0.12. 2) The maximum compressive stress in the screw, bearing pressure on the thread, and shearing stress in the thread. 3) Efficiency of the straightener. Nut T 150 ↓ Hand wheel Screw 100 150- 400 All dimensions in mm