A health psychologist claims that the more final exams a student has during finals weeks, the morestressed they are.They want to test this experimentally by having 6 students receiving additional finals in their fallsemester and then assessing sleep during finals (µ1 = mu1). Then the same 6 students receive noadditional finals in their spring semester and are assessed on their sleep during finals (u2 = mu2) andthey want to assess if the difference in sleep with no additional finals relative to additional finalswith mu1 - mu2.µ1 = mu1 = Additional finals andl2 = mu2 = No additional finalsThey get the following data:Additional finalsNo Additional finals985878498693736044658762What would be your t-statistic for this research? Please report to 4 decimal places.

Answered: Image /qna-images/answer/d3db6f0f-d703-4bbc-b1e1-af185f27aea5.jpg

Answered: A health psychologist claims that the…

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 8CR

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What is an experiment?
A mutation in Gene A is thought to be associated with a disease. The mutation in Gene A is found in 5% of the population. 2% of the whole population is diagnosed with disease B at some point in their life time. 1% of the population both has the mutation and also gets diagnosed with the disease in their life time. Is the provided data adequate to test the independency of mutation in Gene A and occurrence of Disease B? If it is not, what other information or data is needed to test the independency? What is the probability of Disease B, among the individuals with the mutation in Gene A? What is the probability of having the mutation in Gene A among the individuals with Disease B? If an individual has the mutated Gene A, what is their Relative Risk of developing the disease?
People often wait till middle age to worry about having a healthy heart. However, recent studies have shown that earlier monitoring of risk factors such as blood pressure can be very beneficial (The Wall Street Journal, January 10, 2012). Having higher than normal blood pressure, a condition known as hypertension, is a major risk factor for heart disease. Suppose a large sample of individuals of various ages and gender was selected and that each individual’s blood pressure was measured to determine if they have hypertension. For the sample data, the following table shows the percentage of individuals with hypertension. Develop a side-by-side bar chart with age on the horizontal axis, the percentage of individuals with hypertension on the vertical axis, and side-by-side bars based on gender. What does the display you developed in part (a), indicate about hypertension and age? Comment on differences in gender. Age Male Female 20 - 34 11.0% 9.0% 35 – 44…
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Find the mean and standard deviation for the family history group, the before treatment group, and the after treatment group.
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a side-by-side boxplot to compare the variables BP-Before-Exp and BP-After-Exp.
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a scatterplot to display the relationship and find the correlation between age and BP-Before Exp.
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a histogram to represent the family BP history, the subjects' BP before treatment and the subjects' BP after treatment.
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a scatterplot to display the relationship and find the correlation between BP-Before-Exp and BP-After-Exp.
The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Generate at least two different cross tabulations.
Your research group wants to explore the possibility that a particular kind of Tibetan meditation (shamata meditation) increases the capacity of iconic memory. You go to a center where experienced Tibetan Buddhist meditators regularly practice. You randomly select 10 of these people to participate in your experiment. Your dependent variable is the number of digits recalled from iconic memory. You test them before and after a 5 weeks' intensive meditation course. You predict that their iconic memory will be enhanced (better recall) as a result of the attentional training that the meditation gives. Here is the data you collect: Before: 6;6;6;7;5;7;5;5;6;6 After: 8;7;7;8;7;8;6;7;6;8 1. What is the null hypothesis? What is the alternative hypothesis? (use symbols and not words)
Anna Fisher and colleagues (Fisher et al., 2014) predicted that kindergarten students should learn better in undecorated classrooms compared to decorated classrooms, because students should be less distracted in sparse classrooms without distractions such as posters, maps, children's artwork, etc. They had a group of 12 kindergarten age children participate in a science lesson in a classroom without decorations and a classroom with decorations. The students took a test on the material immediately after each lesson (scores range from 0 to 20). Below are the number of correct responses on both tests for each child. Do kindergarteners learn better in an undecorated compared to a decorated environment? Undecorated Decorated Subject (X1) (X2) 1 19 17 1. State the null and alternative 15 14 hypotheses using the appropriate 16 symbols. State whether the test is one- 15 or two-tailed 14 4 19 17 15 6. 2. State the degrees of freedom and 18 18 13 14 identify the critical value(s) at an alpha 8.…
The inflammation caused by osteoarthritis of the knee can be very painful and can inhibit movement. Leech saliva contains anti-inflammatory substances. To study the therapeutic effect of attaching four to six leeches to the knee for about 70 minutes, 51 volunteers were randomly assigned to receive either the leech treatment or a topical gel, diclofenac. This summary table gives the results of a pretreatment measure of the amount of pain reported by the two groups, before beginning therapy. A higher score means more pain. The researchers hoped that the randomization would result in two comparable groups with respect to this variable. You may assume that the pain scores are approximately normal for each group. Leech (Group 1): x⎯⎯⎯x¯ = 52.4, ss = 13.9, nn = 24Topical gel (Group 2): x⎯⎯⎯x¯ = 52, ss = 16.6, nn = 27 Unless otherwise stated, give your answers to three decimal places. Construct a 99% confidence interval for the difference in average pain score. Give your answers to two…

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