A ground state H-atom absorbs a photon of wavelength 94.91 nm, and its electron attains a higher energy level. The atom then emits two photons: one of wavelength 1281 nm to reach an intermediate level, and a second to return to the ground state. a. What higher level did the electron reach? (Ans. n = 5) b. What intermediate energy level did the electron reach? (Ans. n =3) c. What was the wavelength of the second photon emitted? (Ans. 1.02 x 107 m)

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12. A ground state H-atom absorbs a photon of wavelength 94.91 nm, and its electron attains a higher energy level. The
atom then emits two photons: one of wavelength 1281 nm to reach an intermediate level, and a second to return to the
ground state.
a. What higher level did the electron reach? (Ans. n = 5)
b. What intermediate energy level did the electron reach? (Ans. n =3)
c. What was the wavelength of the second photon emitted? (Ans. 1.02 x 107 m)
Transcribed Image Text:12. A ground state H-atom absorbs a photon of wavelength 94.91 nm, and its electron attains a higher energy level. The atom then emits two photons: one of wavelength 1281 nm to reach an intermediate level, and a second to return to the ground state. a. What higher level did the electron reach? (Ans. n = 5) b. What intermediate energy level did the electron reach? (Ans. n =3) c. What was the wavelength of the second photon emitted? (Ans. 1.02 x 107 m)
Expert Solution
Step 1

The Rydberg's equation for the electronic transition in the H atom is as follows:

hcλ=RH1ni2-1nf2

Here:

c is the velocity of light.

λ is the wavelength of the radiation or photon.

RH is the Rydberg's constant with value 2.18 x 10-18J.

ni is the initial state of the electron/lower level.

nf is the final state of the electron/higher level.

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