a) From the graph, estimate how long it takes for the ball to reach the ground again and compare it to your calculated value, i.e. calculate the percent error. b) From the graph, estimate the maximum height of the ball and compare it to your calculation, i.e. calculate the percent error.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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a) From the graph, estimate how long it takes for the ball to reach the ground again and compare it to your calculated value, i.e. calculate the percent error.

b) From the graph, estimate the maximum height of the ball and compare it to your calculation, i.e. calculate the percent error.

x (m)
Position as a function of time
t = 4.00 s
10
(s)
0.0 0.4 0.8 1.2 1.6 2.0 2.4 2.8 3.2 3.6 4.0
v (m/s)
Velocity as a function of time
20
>t (s)
0.4 0.8 1.2 1.6 2.0 2.4 2.8 32 3.6 4.0
-20
a (m/s/s)
Acceleration as a function of time
10
►t (s)
0.4 0.8 1.2 1.6 2.0 2.4 2.8 3.2 3.6 4.0
-10
20
001|0||||O||
Transcribed Image Text:x (m) Position as a function of time t = 4.00 s 10 (s) 0.0 0.4 0.8 1.2 1.6 2.0 2.4 2.8 3.2 3.6 4.0 v (m/s) Velocity as a function of time 20 >t (s) 0.4 0.8 1.2 1.6 2.0 2.4 2.8 32 3.6 4.0 -20 a (m/s/s) Acceleration as a function of time 10 ►t (s) 0.4 0.8 1.2 1.6 2.0 2.4 2.8 3.2 3.6 4.0 -10 20 001|0||||O||
Expert Solution
Step 1

We are taking the x-direction to be the vertical direction.

(a)From the graph, the time taken by the ball to reach the ground is 4.0s. 

The ball is a projectile. The equation for the time period of a projectile is given by

T=2v0yg  (1)

Here, v0y is the initial vertical velocity of the ball and g is the magnitude of the acceleration due to gravity.

From the second graph, the initial vertical velocity is 20m/s.

v0y=20 m/s

From the third graph

g=10 m/s2

Substituting the values in equation (1),

T=220 m/s10 m/s2=4.0 s

Since the value from the graph and the calculated value are the same, the percentage error will be zero.

 

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