A frame supports both a linear distributed load and a concentrated moment, as shown in the figure below. The distributed load has a magnitude qo = 110 N/m at point B which decreases linearly to zero at point C. The concentrated moment has a magnitude Mc = 53 Nm and acts at point C. The frame is held in equilibrium by a pin at point A and a cable BD. The horizontal and vertical dimensions are given as: L₁ = 4 m, L2 = 1.5 m, and L3 = 9 m. Neglect the thickness and weight of the frame for this analysis. Determine the internal normal force (P), internal shear force (V), and internal bending moment (M) at the following locations: Y L3 D qo B f A e C Mc

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.2.10P: The device shown in the figure consists of a prismatic rigid pointer ABC supported by a uniform...
icon
Related questions
icon
Concept explainers
Question

please help me solve and explain this problem please 

A frame supports both a linear distributed load and a concentrated moment, as shown in the figure below. The
distributed load has a magnitude q, = 110 N/m at point B which decreases linearly to zero at point C. The
concentrated moment has a magnitude Mc = 53 Nm and acts at point C. The frame is held in equilibrium
by a pin at point A and a cable BD. The horizontal and vertical dimensions are given as: L₁ = 4 m,
L₂ = 1.5 m, and L3 = 9 m. Neglect the thickness and weight of the frame for this analysis. Determine the
internal normal force (P), internal shear force (V), and internal bending moment (M) at the following
locations:
Pe=
Ve=
M₂ =
X
P₁ =
V₁ =
Mf
L3
=
(b) Point f, which lies 7 m above point A.
Note: Express our answers following the standard positive sign convention described in the Internal Loads -
Positive Sign Convention document.
(a) Point e, which lies 0.75 m to the left of point C.
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
N
N
90
B
N
N
of
N-m
Mc
N-m
Transcribed Image Text:A frame supports both a linear distributed load and a concentrated moment, as shown in the figure below. The distributed load has a magnitude q, = 110 N/m at point B which decreases linearly to zero at point C. The concentrated moment has a magnitude Mc = 53 Nm and acts at point C. The frame is held in equilibrium by a pin at point A and a cable BD. The horizontal and vertical dimensions are given as: L₁ = 4 m, L₂ = 1.5 m, and L3 = 9 m. Neglect the thickness and weight of the frame for this analysis. Determine the internal normal force (P), internal shear force (V), and internal bending moment (M) at the following locations: Pe= Ve= M₂ = X P₁ = V₁ = Mf L3 = (b) Point f, which lies 7 m above point A. Note: Express our answers following the standard positive sign convention described in the Internal Loads - Positive Sign Convention document. (a) Point e, which lies 0.75 m to the left of point C. number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) N N 90 B N N of N-m Mc N-m
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 19 images

Blurred answer
Knowledge Booster
Statics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning