A footing, 2 m square, rests on a soft clay soil with its base at depth of 1.5 m from ground surface. The clay stratum is 3.5 m thick and is underlain by a firm sand stratum. The clay soil has the following properties: W₁ = 30%; w₁ = 40%; G = 2.70; p = 0; c = 0.5 kg/cm² n 8 It is known that the clay stratum is normally consolidated. using Skempton's equation, determine the net safe bearing capacity of the footing. Compute the settlement that would result if this load intensity were allowed to act on the footing. Natural water table is quite close to the ground surface. 3.5 m M4M 2.5 m A 1.5 m 2 mx 2 m- A Soft clay W₁ = 30% W₁ = 40% G = 2.70 $₁ = 0° c₁ = 0.5 kg/cm² Sand 2

Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter17: Settlement Of Shallow Foundations
Section: Chapter Questions
Problem 17.1P
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A footing, 2 m square, rests on a soft clay soil with its base at depth of 1.5 m
from ground surface. The clay stratum is 3.5 m thick and is underlain by a
firm sand stratum. The clay soil has the following properties:
W₁ = 30%; w₁ = 40%; G = 2.70; p = 0; c = 0.5 kg/cm²
n
S
It is known that the clay stratum is normally consolidated. using Skempton's
equation, determine the net safe bearing capacity of the footing. Compute
the settlement that would result if this load intensity were allowed to act on
the footing. Natural water table is quite close to the ground surface.
3.5 m
4X
2.5 m
A
1.5 m
2 mx 2 m-
A
Soft clay
W₁ = 30%
W₁ = 40%
G = 2.70
$₁ = 0°
c₁ = 0.5 kg/cm²
Sand
2
Transcribed Image Text:A footing, 2 m square, rests on a soft clay soil with its base at depth of 1.5 m from ground surface. The clay stratum is 3.5 m thick and is underlain by a firm sand stratum. The clay soil has the following properties: W₁ = 30%; w₁ = 40%; G = 2.70; p = 0; c = 0.5 kg/cm² n S It is known that the clay stratum is normally consolidated. using Skempton's equation, determine the net safe bearing capacity of the footing. Compute the settlement that would result if this load intensity were allowed to act on the footing. Natural water table is quite close to the ground surface. 3.5 m 4X 2.5 m A 1.5 m 2 mx 2 m- A Soft clay W₁ = 30% W₁ = 40% G = 2.70 $₁ = 0° c₁ = 0.5 kg/cm² Sand 2
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