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A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. :0: :O-H 个回 A) The arrow points at the proton that is electron deficient. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. B) The arrow points at the proton that is electron rich. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow fro+ the base (HO) to the proton showing the formation of a new bond. The second arrow

A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. :0: :O-H 个回 A) The arrow points at the proton that is electron deficient. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. B) The arrow points at the proton that is electron rich. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow fro+ the base (HO) to the proton showing the formation of a new bond. The second arrow

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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UL LTU LTU ( X edu.co * F2 # 3 E UL LTU X :O: DII F3 UL LTU X $ 4 R F H F4 G perio X % 5 T G -H TO RevieXxG Krusi x F5 A 6 Question 4 of 21 Y H OF F6 & 7 C Che U | Che X F7 1 C 8 Cheg X PrtScn G Ident X F8 K electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow from the base (HO) to the proton showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the carboxylic acid breaking the O-H bond. Home D) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a high electron density. The electrons follow the arrow from the base (HO) to the proton showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the carboxylic aci + breaking the O-H bond. ( b Ansv x + 9 F9 O End ) P 0 Tp SO ^ F10 P ENG @D PgUp 0 F11 Submit 3 [ 9:34 PM 10/11/2022 PgDn = F12
Transcribed Image Text:UL LTU LTU ( X edu.co * F2 # 3 E UL LTU X :O: DII F3 UL LTU X $ 4 R F H F4 G perio X % 5 T G -H TO RevieXxG Krusi x F5 A 6 Question 4 of 21 Y H OF F6 & 7 C Che U | Che X F7 1 C 8 Cheg X PrtScn G Ident X F8 K electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow from the base (HO) to the proton showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the carboxylic acid breaking the O-H bond. Home D) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a high electron density. The electrons follow the arrow from the base (HO) to the proton showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the carboxylic aci + breaking the O-H bond. ( b Ansv x + 9 F9 O End ) P 0 Tp SO ^ F10 P ENG @D PgUp 0 F11 Submit 3 [ 9:34 PM 10/11/2022 PgDn = F12
Nee X app.101edu.co 2 N UL LTU X X * F2 # 3 E D UL LTU € X tert :O: DII C Question 4 of 21 A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. UL LTU EX G peric X $ 4 R F ♫x H V % 5 T G Revic X F5 B H ^ 6 G Krus X C|Che X C Cheg X H F6 & 8 7 N U PrtScn 8 1 M K b Ansv x Home ( 9 O A) The arrow points at the proton that is electron deficient. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. L B) The arrow points at the proton that is electron rich. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow fro + the base (HO) to the proton showing the formation of a new bond. The second arrow ) End 0 + F10 12 P A ☆ 4 ENG Tp S : PgUp ||| { O [ Submit ? PgDn 9:34 PM 10/11/2022 F12
Transcribed Image Text:Nee X app.101edu.co 2 N UL LTU X X * F2 # 3 E D UL LTU € X tert :O: DII C Question 4 of 21 A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. UL LTU EX G peric X $ 4 R F ♫x H V % 5 T G Revic X F5 B H ^ 6 G Krus X C|Che X C Cheg X H F6 & 8 7 N U PrtScn 8 1 M K b Ansv x Home ( 9 O A) The arrow points at the proton that is electron deficient. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. L B) The arrow points at the proton that is electron rich. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow fro + the base (HO) to the proton showing the formation of a new bond. The second arrow ) End 0 + F10 12 P A ☆ 4 ENG Tp S : PgUp ||| { O [ Submit ? PgDn 9:34 PM 10/11/2022 F12
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