A crate is sliding toward the right on a horizontal track at a constant speed of 0.55 m/s. The vector sum of all the forces acting on this crate must point right. A. False
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A crate is sliding toward the right on a horizontal track at a constant speed of 0.55 m/s. The vector sum of all the forces acting on this crate must point right.
A. False
B. True
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- 9. A train pulls out of a station along straight with a horizontal track five identical freight cars behind it, each of which weighs 90.0 KN. The train 25.0 m/s reaches a speed of within 5.0 mins. Of starting out. Assuming the engine pulls with a this interval, with a magnitude of a force does the coupling between cars pulls forward on the last of the freight cars? Ignore air constant force during resistance and friction the freight cars. a. 733.94N c. 45, 871.56N b. 458.72N d. 2.30KN d. 459 KNTwo forces act on a box. F₁ = 44.8 N (East) and F₂ = 17.6 N (North). What is the magnitude and direction of the net force acting on the box? Select one: a. 62.4 N @ 21.4° (North of East) 48.1 N @ 21.4° (North of East) C. c.62.4 N @ 21.4° (East of North) d. 48.1 N @ 21.4° (East of North)The 1.0 kg block in the figure is tied to the wall with a rope. It sits on top of the 2.0 kg block. The lower block is pulled to the right with a tension force of 20 N. The coefficient of kinetic friction at both the lower and upper surfaces of the 2.0 kg block is μkμk = 0.42. What is the acceleration of the 2.0 kg block? Express your answer with the appropriate units. The anwer is NOT 3.826 1.6 3.7 7.942
- The forces F1, F2, F3, ..... , Fn acting on an object are in equilibrium if the resultant force is the zero vector: F1 + F2 + F3 + g + ........+ Fn = 0. The given forces F1 = 3i - 5j, F2 = 6i + 2j are acting on an object. Then, a. Find the resultant force. b What additional force is required for the given forces to be in equilibrium?m. m A mass m₁ = 5.5 kg rests on a frictionless table and connected by a massless string to another mass m2 3.6 kg. A force of magnitude F = 34 N pulls m₁ to the left a distance d = 0.74 m. =Two masses, m₁ = 65 kg, and m₂ = 81 kg are attached by a massless rope over a massless, frictionless pulley, as shown. Mass m₂ rests on a smooth, frictionless inclined plane of 40°. m₁ m₂ Ꮎ a. Calculate the magnitude of the acceleration of m₁. b. Is m₁ accelerating up or down? Explain. c. Calculate the tension in the rope.
- Suppose an empty flatbed railroad car sits on a track as shown below, with a person pulling on a rope with a force of 280 Newtons in a direction of 0 = 25°. 廿 railroad car Since the railroad car can't move in the direction that the person is pulling, not all of the force he is exerting works to move the car down the track. a. How much force is the person exerting toward the right (the force that would go towards trying to move the car)? Newtons Preview b. The first person wasn't able to move the railroad car. Suppose a second rope is attached as shown below, and someone pulls on the rope in the direction B = 21° south of east. II railroad car If it takes 615 N to get the railroad car moving (even if only slightly), how much force must the second person exert in the given direction to get the railroad car to move? Newtons PreviewA rocket sled decelerates at a rate of a =197 m/s^2. Its passenger has a mass of 73.5 kg. a. Calculate the horizontal component of the force the seat exerts against his body. b. Compare his weight by using a ratio. The horizontal component of the forice is how many times his weight. Calculate the magniture and direction of the total force the seat exerts against his body.A pulley is suspended by a cord C. Suppose that m1= 1.0 kg and m2 = 3.1 kg . Determine the tension in the cord that supports the pulley C after the masses are released and before one hits the ground. Ignore the mass of the pulley and cords.
- The vertical component of the acceleration of a sailplane is zero when the air pushes up against its wings with a lift force of 4.00 kN. a. Assume that the only forces on the sailplane are that due to gravity and that due to the air pushing up against its wings. What will be the gravitational force on Earth due to the sailplane? If the force acting is in upward direction, enter a positive value and if the force acting is in downward direction, enter a negative value. (answer in kN) b. If the wing stalls and the upward force decreases to 1.71 kN, what is the acceleration of the sailplane? If the acceleration is upward, enter a positive value and if the acceleration is downward, enter a negative value answer in m/s^2Mr. One is pushing a cart with a force of F1 = 15.00 N due north. Mr. Two is pushing the same cart with a force of F2 = 25.00 N due northeast. Mr. Three is pushing the cart a force F3 so that the cart is in equilibrium. Find force F3 so that . First, we calculate the vector sum by component method. The x-component of is and the y-component is . The x-component of is and the y-component is . Adding the components, we can express the resultant vector in unit vector component form: = + Since we want to find , it follows that . Thus, = + The magnitude of is F3 = N.A rope is attached to a box. The box is placed on an inclined plane. The box has a mass of 50 kg. I would like to lower the box downward. I am holding it with a force F equal to 100 N. Ignore friction. The angle θ = 30o A. Does the box move downward or actually stay at rest on the inclined plane? B. Determine the acceleration of the box. C. Friction is present and the coefficient of kinetic friction is 0.2. Determine the new acceleration of the box
