A continuous function y = f(x) is known to be negative at x = 2 and positive at x = 5. Why does the equation f(x) = 0 have at least one solution between x = 2 and x = 5? Illustrate with a sketch. Why does the equation f(x) = 0 have at least one solution between x = 2 and x = 5? O A. f(x)=0 has at least one solution between x=2 and x = 5 because all continuous functions have at least one zero over any nonempty closed interval. O B. f(x)=0 has at least one solution between x = 2 and x = 5 because f is a continuous function on the closed interval [2, 5], and if yo is any value between f(2) and f(5), then yo = f(c) for some c in [2, 5]. OC. f(x)=0 has at least one solution between x = 2 and x = 5 because f(x) must pass through all values between f(2) and f(5), regardless of whether f is continuous. Choose a graph below that illustrates the situation. O A. 10 Q O B. C Q Q G O C. Q O D. 21 Q

A continuous function y = f(x) is known to be negative at x = 2 and positive at x = 5. Why does the equation f(x) = 0 have at least one solution between x = 2 and x = 5? Illustrate with a sketch. Why does the equation f(x) = 0 have at least one solution between x = 2 and x = 5? O A. f(x)=0 has at least one solution between x=2 and x = 5 because all continuous functions have at least one zero over any nonempty closed interval. O B. f(x)=0 has at least one solution between x = 2 and x = 5 because f is a continuous function on the closed interval [2, 5], and if yo is any value between f(2) and f(5), then yo = f(c) for some c in [2, 5]. OC. f(x)=0 has at least one solution between x = 2 and x = 5 because f(x) must pass through all values between f(2) and f(5), regardless of whether f is continuous. Choose a graph below that illustrates the situation. O A. 10 Q O B. C Q Q G O C. Q O D. 21 Q

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 91E

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