A constant applied force ?pFp of 15.0 N15.0 N pushes a box with a mass ?=7.00 kgm=7.00 kg a distance ?=15.0 mx=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Assuming that the box starts from rest, what is the final velocity ?fvf of the box at the 15.0 m15.0 m point? If there were no friction between the box and the floor, what applied force ?newFnew would give the box the same final velocity?
A constant applied force ?pFp of 15.0 N15.0 N pushes a box with a mass ?=7.00 kgm=7.00 kg a distance ?=15.0 mx=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Assuming that the box starts from rest, what is the final velocity ?fvf of the box at the 15.0 m15.0 m point? If there were no friction between the box and the floor, what applied force ?newFnew would give the box the same final velocity?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter7: Gravity
Section: Chapter Questions
Problem 1PQ: We use the terms sunset and sunrise. In what way are these terms misleading?
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A constant applied force ?pFp of 15.0 N15.0 N pushes a box with a mass ?=7.00 kgm=7.00 kg a distance ?=15.0 mx=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150.
Assuming that the box starts from rest, what is the final velocity ?fvf of the box at the 15.0 m15.0 m point? If there were no friction between the box and the floor, what applied force ?newFnew would give the box the same final velocity?
![Fp
m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45a38078-7db9-4eb5-9b9c-df964c9c580e%2F7b74b580-99a9-45ba-8b7d-5443f11ca0c3%2Flp002b8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Fp
m
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