A column is made from a rectangular bar whose cross section is 5.1 cm by 8.7 cm. If the height of the column is 2 m, what is the maximum load it can support? The material has E = 200 GPa and oy = 250 MPa. Express your answer with appropriate units to three significant figures.
Q: A steel column (E = 200 GPa) is 9 m long, embedded in a one end and supported on the other. If the…
A:
Q: Rod AB consists of two cylindrical portions AC and BC, each with a cross-sectional area of 1950 mm2.…
A:
Q: 8. A steel bar of 40mm x 40mm square cross-section is subjected to an axial compressive load of…
A: Answer: The elongation of the bar will be ◆ When 30mm × 30mm square section : 2.22 mm. ◆ When 40mm…
Q: Determine the reactions needed to support the load. Please, present your work in organized and neat…
A:
Q: Determine the largest axial load P that can be safely supported by a flat steel bar consisting of…
A:
Q: Two columns have the following parameters: Column A Column B Length Cross sectional area 1.5m 2m…
A: It is the very basic but comparative question of theory of columns portion of strength of material.…
Q: A steel wire is 10 meters long, hanging vertically supports a tensile load of 2000 N. Determine the…
A: Write the given data. L=10 mP=2000 Nσmax=140 MPaδ=5 mmE=200 GPa
Q: Question 5 of 5 A column with a length of 8 m that is pinned on both ends. The column is made of a…
A:
Q: A steel [E = 25500 ksi] pipe column (1) with a cross-sectional area of A1 = 5.60 in.2 is connected…
A:
Q: A wire 20 m long, weighing 0.8 N per m, and having a cross sectional area of 6.2 mm^2, is suspended…
A: According to the question, length of the wire,L=20mCross sectional area, A=6.2mm2Young's modulus,…
Q: An aluminum [E = 10,000 ksi] control rod with a circular cross section must not stretch more than…
A:
Q: Question 2 5 Points An aluminum bar having a cross-sectional area of 160 mm? carries the axial loads…
A:
Q: Rod AB consists of two cylindrical portions AC and BC, each with a cross-sectional area of 1950 mm2.…
A:
Q: A 1-in.-diameter steel circular rod is subject to a tensile load that reduces its cross-sectional…
A:
Q: A bar of chocolate has length, thickness, and width measurements of 15mm each. The load applied to…
A:
Q: What is the minimum load needed for a bar of chocolate to break if it has a thickness of 10mm, a…
A: Given, Thickness of bar,t=10mmLength of the bar,L=0.095mwidth of the bar,w=0.05mFlexural stress of…
Q: An axially loaded member 600 mm long is carrying a tensile load of 40 kN. Its maximum stress is 100…
A: To find : The minimum area of body. Given : The tensile load is P=40 KN The maximum stress is :…
Q: The pin-connected structure consists of two cold-rolled steel [E = 28,000 ksi] bars (1) and a bronze…
A:
Q: An aluminum [E = 10,000 ksi] control rod with a circular cross section must not stretch more than…
A:
Q: 3. A solid aluminum cylinder with an initial diameter of d = 10mm is under a compressive load P = 15…
A: Given data:
Q: A steel [E = 200 GPa] rod with a circular cross section is 5 m long. Determine the minimum diameter…
A: Given data: The youngs modulus of the rod is, E=200 GPa. The length of the rod is, L=5 m. The…
Q: A metallic rod made of steel as shown below is used as support for a signage with length equal to…
A:
Q: A circular column of length 1.8 m has Euler's crippling load of 2 kN. If the diameter of the column…
A: Given Length, L = 1.8 m Diameter, d = 15% reduction Load, P = 2 kN Find % Reduction
Q: A steel rod 4 m long and 40 mm diameter is used as a column. Determine the crippling load by Euler's…
A:
Q: 7. A SAE steel column has a circular cross-section of 16 mm in diameter and a length of 320 mm. The…
A:
Q: tube of 5m long ,40mm inner diameter and 80mm outer diameter is used as an euler column. Assuming…
A:
Q: A column with circular cross section of 30 mm diameter has its both ends fixed and is subjected to…
A: Solution:
Q: An aluminium strut 16 ft long has a rectangular cross section 2 in by 3.5 in. A bolt through each…
A:
Q: 5. Two C310x45 channels are latticed together so they have equal moments of inertia about the…
A: Write the formula for proportional limit to calculate the critical load. P2A=σ Here, σ is the…
Q: load of 200 KN. If the length of the bar is 2 m and E = 200 GPa. What will be the elongation of the…
A:
Q: composite column is formed by placing a steel bar 20 mm diameter and 200 mm long, inside an alloy…
A:
Q: A ladder with a uniform cross-section has a length of 4.80-foot long. It weighs W Ib. It is arranged…
A:
Q: Part A The two bars shown in the figure below (Eigure 1) are made of a material that has the…
A:
Q: A steel rod 4 m long and 40 mm diameter is used as a column. Determine the crippling load by Euler’s…
A: L= 4 md=40 mmE=2×105 N/mm2Pc=π2EILef2I=π64×404=125663.706 mm4aBoth end are hinged In this case…
Q: 2. A bar having a length of 5 in. and cross-sectional area of 0.8 in? is subjected to an axial force…
A: Given:L=5 inA=0.8 in2F=8000 lb∆L=0.003 in
Q: An alloy bar 800 mm long and 200 mm in cross-section is held between two rigid plates and is…
A: Given:- Axial load=200kn Cross-sectional area:-200mm2 To find:- Reaction forces at end and…
Q: A cylindrical rod of copper (E = 110 GPa, 16 × 106 psi) having a yield strength of 240 MPa (35,000…
A: Given data: E=110 GPaσy=240 MPaF=6670 NL=390 mmδ=0.5 mm Need to determine the diameter of the rod.
Q: 36. A mild steel bar is 40cm long. The lengths of parts of AB and BC of bar 20cm each. It is loaded…
A: D1=Diameter of Mild steel bar 1 (AB)=2 cm=0.02 mD2=Diameter of Mild steel bar 2 (BC)=1 cm=0.01…
Q: a 4.4 m long aluminum bar with a modulus of elasticity of 70 gpa is subjected to a tensile stress of…
A: Stress is defined as the intensity of force acting over a unit area. Normal strain is the ratio of…
Q: A square steel bar is 50 mm on a side and 250 mm long. It is loaded by an axial tensile force of 200…
A: GIVEN DATA- SIDE OF SQUARE a=50mm L=250mm E=200GPa P=200KN POISSON RATIO=0.3 WE HAVE TO FIND…
Q: The cylindrical rod is made of steel with E = 30000 ksi and u = 0.3. P 10 kips d Id = lin. L=4 ft AL…
A: Option c is correct. Here negative sign shows that final diameter is lesser than initial diameter.
Q: Find the critical load of a Euler’s column having 4 m length, 50 mm x 100 mm cross section and…
A:
Q: A mid steel column 5 m long ad 50 mm dia.Which is fixed at end and free at the other end. Determine…
A:
Q: Problem 1: A steel rod with a cross-sectional area of 0.20 in² is stretched between two fixed…
A: Given data: The cross-section area is The 1st temperature is The tensile load is The 2nd…
Q: Q1: 30-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar…
A: Write the torsion equation for the steel bar. Here, G represents the modulus of rigidity, θ…
Q: The rigid bar AC is supported by two axial bars (1) and (2). Both axial bars are made of bronze [E =…
A: Givenbar material →bronzeE=100Gpaα=18×10-6mm/mmοCA1=180mm2A2=380 mm2L1=1290 mmL2=2000 mma=590…
Q: 2. A 45-cm long rod of 1020 grade steel will be used as a frame support. It will be subjected to a…
A:
Q: The rigid beam shown in Figure AN- 12 is suspended by three cables. The beam is horizontal prior to…
A: Draw free body diagram of beam
Q: A leaf spring 1 m long is made up with steel plates with width equal to 6 times its thickness.…
A:
Q: A steel bar 40 mm x 40 mm square cross-section is subjected to an axial compressive load of 200 kN.…
A: Data given- A = 40 mm × 40 mm = 1600 × 10-6 m2 P = 200 × 103 N L = 2 m E = 200 × 109 Pa
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
- A round bar of 10 mm diameter is made of aluminum alloy 7075-T6 (see figure). When the bar is stretched by axial forces P, its diameter decreases by 0.0 16 mm. Find the magnitude of the load P. Obtain the material properties from Appendix 1.Two steel wines support a moveable overhead camera weighing W = 28 lb (see figure part a) used For close-up to viewing of field action at sporting, events. At some instant, wire I is at an angle a = 22° to the horizontal and wire 2 is at angle fi = 40°. Wires I and 2 have diameters of 30and 35 mils, respectively. (Wire diameters are often expressed in mils; one mil equals 0.001 in.) (a) Determine the tensile stresses s and s2 in the two wires. (b) If the stresses in wires 1 and 2 must be the same, what is the required diameter of wire 1 ? (c) To stabilize the camera for windy outdoor conditions, a third wire is added (see figure part b). Assume the three wires meet at a common point coordinates (0, 0. 0) above the camera at the instant shown in figure part b. Wire I is attached to a support at coordinates (75 ft, 48 ft, 70 Ft). Wire 2 is supported at (-70 ft. 55 ft, 80 Ft). Wire 3 is supported at (-10 ft. -85 Ft, 75 ft). Assume that all three wires have a diameter of 30 mils. Find the tensile stresses in all three wiresBar (1) in Figure PP1.2-6 has a cross-sectional area of 0.75 in.². If the stress in bar (1) must be limited to 30 ksi, determine the maximum load P that may be supported by the structure. Answer in kips rounded-off to 2 decimal n 6 ft B (1) Figure PP1.2-6 4 ft 5 OF 6 QUESTIONS REMAI
- You are given a square rod of 6061-T6 aluminum (cross-section = 4mm X 4mm, length = 2.3m). The material has a Young’s modulus of 72 GPa. If a tensile load of 3 kN is applied parallel to the 2.3m dimension, what is the change in length of the rod?A column is made from a rectangular bar whose cross section is 5.1 cm by 8.7 cm If the height of the column is 2 m , what is the maximum load it can support? The material has E = 200 GPa and oy = 250 MPa.1. A steel bar 8 m long, hanging vertically supports a tensile load of 2500 N. Neglecting the weight of the bar, calculate the required diameter so that the axial stress will not exceed 130 MPa and the total elongation is not to exceed 6 mm. Use E-200 GPa Answer: D = 4.95 mm 2. A bar having a length of 5 in. and cross-sectional area of 0.8 in² is subjected to an axial force of 8000 Ib. If the bar stretches 0.003 in., determine the modulus of elasticity of the material. Assume that the material behave elastically. Answer: E= 16.67 x 10" ksi 8000 lb 8000 lb -5 in-
- A compound steel (E = 30,000 ksi) bar is subjected to the loads shown. Bar (1) has a cross-sectional area of A₁ = 0.45 in.² and a length of L₁ = 85 in. Bar (2) has an area of A₂ = 0.45 in.² and a length of L2 = 80 in. Bar (3) has an area of A3 = 0.19 in.² and a length of L3 = 40 in. The loads and angles are P = 24 kips, a = 30°, Q = 10 kips, ß = 56°, and R = 11 kips. Determine the vertical deflection of end A. P B D B A (1) (2) VR U O L₁ L2 L3A compound steel (E = 30,000 ksi) bar is subjected to the loads shown. Bar (1) has a cross-sectional area of A₁ = 0.40 in.² and a length of L₁ = 120 in. Bar (2) has an area of A₂ = 0.40 in.² and a length of L₂ = 100 in. Bar (3) has an area of A3 = 0.13 in.² and a length of L3 = 35 in. The loads and angles are P = 26 kips, a = 39%, Q = 14 kips, B = 61°, and R = 12 kips. Determine the vertical deflection of end A. A downwards deflection is positive, while an upwards deflection is negative. D (1) L₁ (2) Answer: ỖA = i B A R L2 L3 in.Question 1b: A steel bar of 40 mm X 40 mm square cross-section is subjected to an axial compressive load of 200 KN. If the length of the bar is 2 m and E = 200 GPa. What will be the elongation of the bar?
- Question Two A steel flat of thickness 10 mm tapers uniformly from 60 mm at one end to 40 mm at other end in a length of 600 mm. If the bar is subjected to a load of 80 kN, find its extension. Take E = 2 x 10 MPa. What is the percentage error if average area is used for calculating extension?10-mm-diameter rod of 3003-H14 aluminium alloy is subjected to a 6-kN tensile load. Calculate the resulting rod diameter. Calculate the diameter if this rod is subjected to a 6-kN compressive load, given that the elastic modulus =70 GPa and poisson ratio=0.331. A steel rod of 25 mm diameter is enclosed centrally in a copper hollow tube of external diameter 40 mm and internal diameter 30 mm. The composite bar is then subjected to an axial load of 4500 N.If the length of each bar is equal to 130 mm, calculate: 1. The stress in the rod and the tube 2. Load carried by each bar. Take Es=2.1x105 N/mm2 and Ec=1.1x105 N/mm2