A clean, dry and open empty flask is being heated in a water bath. Under which conditions before or after heating does the flask contain more gas molecules? Explain. The flask in problem 1 is allowed to cool back to room temperature. Account for the volume occupied by the gas and the number of gas molecules when the gas is cooled to room temperature. Why is it necessary to immerse the flask both in hot and cold water for 5 minutes before taking the temperature?
A clean, dry and open empty flask is being heated in a water bath. Under which conditions before or after heating does the flask contain more gas molecules? Explain. The flask in problem 1 is allowed to cool back to room temperature. Account for the volume occupied by the gas and the number of gas molecules when the gas is cooled to room temperature. Why is it necessary to immerse the flask both in hot and cold water for 5 minutes before taking the temperature?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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- A clean, dry and open empty flask is being heated in a water bath. Under which conditions before or after heating does the flask contain more gas molecules? Explain.
- The flask in problem 1 is allowed to cool back to room temperature. Account for the volume occupied by the gas and the number of gas molecules when the gas is cooled to room temperature.
- Why is it necessary to immerse the flask both in hot and cold water for 5 minutes before taking the temperature?
- The water levels inside and outside the flask when it was submerged in cold bath must be equal before the flask is removed. Explain.
- Name the factors that contributed to the difference between the measured and the computed values of the horizontal displacement (R).
-
Show that during the motion of a simple pendulum the work done by the tension on the string is zero.
-
Show that when a body of mass m is dropped from a height h, the sum of its kinetic and potential energies is constant at any instant and is equal to mgh.
-
How much mechanical work is done in:
-
lifting a 2 – kg brick to a height of 1 m? b. holding the brick 1 m above the floor?
-
it were moving horizontally at 95 km/hr?
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Show that when a body of mass m is dropped from a height h, the sum of its kinetic and potentialenergies is constant at any instant and is equal to mgh.
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