a) Change the following IPv4 addresses from binary notation to dotted-decimal notation. 10000001 00001011 00001011 11101111 ii.11000001 10000011 00011011 11111111
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Q: · Change the following IPV4 addresses from binary notation to dotted-decimal notation. a. 10000001…
A: Change the following IPV4 addresses from binary notation to dotted-decimal notation .
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A: Invalid FFFF:AAAA:BBBB:CCCC:DDDD:EEEE:FFFF:IIII 1200::AB00:1234::2552:7777:1313
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A: I have provided solution in step2.
Q: Change the following IPV4 addresses from binary notation to dotted-decimal notation. a. 10000001…
A: a. 10000001 00001011 00001011 11101111 10000001 = 129 00001011 = 11 00001011 = 11 11101111 = 239…
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Q: • Change the following IPV4 addresses from binary notation to dotted-decimal notation. a. 10000001…
A: 1. 10000001 00001011 00001011 11101111 10000001 = 129 in decimal (10000001)₂ = (1 × 2⁷) + (0 × 2⁶) +…
- a) Change the following IPv4 addresses from binary notation to dotted-decimal notation.
- 10000001 00001011 00001011 11101111
ii.11000001 10000011 00011011 11111111
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- Change the following IPv4 addresses from binary notation to dotted-decimal notation. I. 10000001 00001011 00001011 11101111 ii.11000001 10000011 00011011 11111111 Show the original (unabbreviated) form of the following IPv6 addresses. FDEC: 74 : : BOFF : 0 : FFFO 0 : 15 : : 1 : 12 :1213 Explain the term Network Address Translation (NAT). What is the need for the network layer? State four advantages that IPv6 has over IPv4Change the following IPV4 addresses from binary notation to dotted-decimal notation. a. 10000001 00001011 00001011 11101111 b. 11000001 10000011 00011011 11111111Determine whether or not the following IPv6 address notations are correct:•::0F53:6382:AB00:67DB:BB27:7332•7803:42F2:::88EC:D4BA:B75D:11CD•::4BA8:95CC::DB97:4EAB•74DC::02BA•::00FF:128.112.92.116
- Provide the compressed format for each of the following IPv6 addresses. Show both rule I and rule 2 of your answer: (i) (ii) FE80:02BD:0000:0000:6000:8001:00A7:B220 2001:0B02:0FC6:0000:0000:0000:0050:A000 2001:6075:75A0:0000:0000:0000:0009:ABBCWrite the simplified version for the following IPv6 address:A700:401:0000:0000:71A0:0000:0000:04A1) Show the original (unabbreviated) form of the following IPv6 addresses. i. FDEC: 74 : : BOFF : 0 : FFFO ii. 0 : 15 : : 1 : 12 :1213
- Write down of shorter form the following IPv6 addresses: 0000:0000:0000:0000:0000:0000:0000:0001, 2001:0DB8:0000:A300:ABCD:0000:0000:0123 Can the following IPv6 addresses exist? (Justify your answer!): 2001:DB9:0000:AA:1::1111; FF02:1001::A1:0000::F; FE80:AAAA:0001:FFFF::0; 8080:0011:AD:5000:99:10.Using the two rules of IPv6 compression, edit each IPv6 address until it is in the shortest form possible. 2b06:0000:0000:1f2b:d77f:0000:0000:89ce 0e56:11c2:0e75:8d23:3528:7e0d:419b:bdce 00eb:0000:0000:0000:d8c1:0946:0272:0879 ad93:a0e4:a9ce:32fc:cba8:15fe:ed90:d768 558c:0000:0000:d367:7c8e:1216:0000:66be 8bfa:99f0:d4c5:0b8c:0f6f:04df:2804:283d 5d66:5ec9:0046:0000:2576:004f:7159:0639 7d2b:00a9:a0c4:0000:a772:00fd:a523:0358 00c8:b434:06ee:ec2f:03c9:01ce:765d:a66b 9930:cafa:0000:0052:04cc:7b7a:0037:27e6. Consult the MIME RFC to find out how base64 encoding handles binary data of a length not evenly divisible by three bytes. The POP3 Post Office Protocol only allows a client to retrieve email, using a password for authentication. Traditionally, to send email a client would simply send it to its server (using SMTP) and expect that it be relayed. (a) Explain why email servers often no longer permit such relaying from arbitrary clients. (b) Propose an SMTP option for remote client authentication. (c) Find out what existing methods are available for addressing this issue.
- S₁ By using advanced encrption standards encrypt the following messag 87 87 87 87 87 87 87 87" with the key (0E32923E A6D0D73) Note: Use these table below for key generation permutation choice 1 table S₁ PC-1 49 57 41 17 25 Tables below for message eneryption 50 26 34 58 1 10 35 2 59 43 19 44 11 3 52 Initial permutation. 55 31 63 47 23 62 7 54 30 38 14 37 61 6 45 IP 21 13 5 20 12 58 50 42 34 26 18 60 52 44 36 28 20 62 54 46 38 30 22 Iteration number tabl 64 56 48 40 32 24 57 49 41 33 25 17 59 51 43 35 27 19 61 53 45 37 29 21 Number of 63 55 47 39 31 23 Iteration Number Left Shifts 1 1 2 1 3 Expansion table 4 5 6 E BIT-SELECTION TABLE 1 2 3 4 5 6 7 8 9 10 11 13 14 15 17 18 19 21 22 23 25 26 27 29 30 31 ▬▬▬▬▬▬▬▬▬▬ 3 23 16 41 30 44 46 7 52 40 49 42 8 9 33 2 1 50 39 6 3 38 51 39 50 42 51 60 46 53 28 10 11 12 13 2 14 15 16 Prmutation choice 2 tabl PC-2 14 17 11 24 1 28 15 21 19 12 26 7 27 13 2 31 47 55 33 48 34 53 29 32 6 4 20 37 2 2 2 2 2 1 2 45 56 36 2 26579586 5 10 8 18 36 15. 22 32 4 8…You have an originating plain text message (in hexadecimal): 41 72 61 62 Use your Student ID number to obtain a 10-bit key as follows: Key (in decimal) = 666. You have to manually cipher the first block of the following plain text message (first 8 bits). The encrypting process will be done using Simplified DES (S-DES). you must explain all steps in detailsAnswer the following questions: The IP address is based on your student number SN as follow: The first byte is 198. The second byte is the 6th and 7th numbers of your SN, for example, if your SN is 438051221, the second byte is The third byte is the 8th and 9th numbers of your SN, for example, if your SN is 438051221, the third byte is The forth byte is 0. Consider a company which owns a license of this IP address. Write this IP address, for example 198.12.21.0 How many hosts at the maximum can be in this network? What are the first and the last addresses given to hosts? The company likes to divide its network into 10 subnets. Determine the necessary number of bits borrowed. Determine the new subnet mask. Determine the maximum number of hosts in each subnet. Fill the following table Subnet Subnet address First host address Last host address Broadcast address 1…