A byte-addressable system with 16-bit addresses ships with a three-way set associative, write-backcache (i.e., each block needs a dirty bit). The cache implements a true LRU replacement policy usingthe minimum number of replacement policy bits necessary to implement it, which means it requires 3bits per set. The tag store requires a total of 264 bits of storage. What is the block size of the cache?(Hint: 264 = 2^8 + 2^3 and please also do not forget that aside from the tag itself, each block needs 1valid bit, 1 dirty bit).
A byte-addressable system with 16-bit addresses ships with a three-way set associative, write-backcache (i.e., each block needs a dirty bit). The cache implements a true LRU replacement policy usingthe minimum number of replacement policy bits necessary to implement it, which means it requires 3bits per set. The tag store requires a total of 264 bits of storage. What is the block size of the cache?(Hint: 264 = 2^8 + 2^3 and please also do not forget that aside from the tag itself, each block needs 1valid bit, 1 dirty bit).
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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A byte-addressable system with 16-bit addresses ships with a three-way set associative, write-back
cache (i.e., each block needs a dirty bit). The cache implements a true LRU replacement policy using
the minimum number of replacement policy bits necessary to implement it, which means it requires 3
bits per set. The tag store requires a total of 264 bits of storage. What is the block size of the cache?
(Hint: 264 = 2^8 + 2^3 and please also do not forget that aside from the tag itself, each block needs 1
valid bit, 1 dirty bit).
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