A block of mass 0.50 kg moves along a straight line and is acted upon by a net force of F(x) = (-6.00 N) + (1.5M) x m speed of v = = 4.00 ¹. S x. When the block is located at x = 2.00 m you notice that it has a (a) Use a graph paper to plot force as a function of position. (b) What is the net work done as the block moves from 2.00 m to 5.00 m? How can this be indicated on your graph? Compute it graphically. (c) Calculate the net work done using the integral definition? Does it agree with what you had graphically? (d) What is the block's kinetic energy at = 2.00 m ? (e) What is the block's kinetic energy when it reaches x = 5.00 m? (f) What is the speed of the block when it reaches x = = 5.00 m?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Energy Of A System
Section: Chapter Questions
Problem 3P: A block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless, horizontal table...
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A block of mass 0.50 kg moves along a straight line and is acted upon by a net force of F(x)
=
(−6.00 N) + (1.5M) x. When the block is located at x = 2.00 m you notice that it has a
m
speed of v= 4.00
4.00
(a) Use a graph paper to plot force as a function of position.
(b) What is the net work done as the block moves from 2.00 m to 5.00 m? How can this be
indicated on your graph? Compute it graphically.
(c) Calculate the net work done using the integral definition? Does it agree with what you
had graphically?
(d) What is the block's kinetic energy at = 2.00 m ?
(e) What is the block's kinetic energy when it reaches x = 5.00 m?
(f) What is the speed of the block when it reaches x = 5.00 m?
Transcribed Image Text:A block of mass 0.50 kg moves along a straight line and is acted upon by a net force of F(x) = (−6.00 N) + (1.5M) x. When the block is located at x = 2.00 m you notice that it has a m speed of v= 4.00 4.00 (a) Use a graph paper to plot force as a function of position. (b) What is the net work done as the block moves from 2.00 m to 5.00 m? How can this be indicated on your graph? Compute it graphically. (c) Calculate the net work done using the integral definition? Does it agree with what you had graphically? (d) What is the block's kinetic energy at = 2.00 m ? (e) What is the block's kinetic energy when it reaches x = 5.00 m? (f) What is the speed of the block when it reaches x = 5.00 m?
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