A ball is equipped with a speedometer and launched straight upward. The speedometer reading three seconds after launch is shown at the right; the ball is moving upward. At what approximate times would the ball display the following speedometer readings? 30 20 10 50 0. 60 Speed m/s 30 20 40 20 30 40 10 50 10 50 60 60 Speed m/s Speed m/s Time (s): Time (s): Check Answer 40
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- 15pa02 GCPRYID80ISPW-barEp8l_bu6Eg/viewform?hr_submission-DChgl5P-F1RoSEA19hcyyvwcS O 13.666 s A pilgrim throws a coin down a well with an initial speed of 2 m/s, and it takes 10s to reach the bottom. How deep is the well? * 2 p 980 m 510 m 1020 m O 490 m pe here to searchBob hits a tennis ball upward with a velocity of ?⃗0 = 30 ?̂ ? ? from a height of 1 meter above the ground. a) Find the velocity of the ball after 2.5 seconds (Answer: 5.5?̂ ? ? ) b) Find the position of the ball at this time (Answer: 45.4?̂ ? ) c) Plot acceleration, velocity, and position vs time.One of my questions got solved and helped me so much thank you! Here’s another one please. Two trains are 9.82km apart. They travel in opposite directions, to each other. Train A has a speed of 5.87 km/h at departure and an acceleration of 0.29m/s squared. Train B has a speed of 20.3m/s at the start and an acceleration of 0.69m/s squared. B. Determine when the trains meet.
- The expression for velocity is given: v=d/t - v0. The variables are given: d= 35.0 meters, t= 9.00 seconds, and v0= 3.00meters/seconds. What is the velocity?A swimmer took a running leap off a high-diving platform. The swimmer was running at 2.8 m/s and hit the water 2.6 seconds later. a) How high was the platform, and b) how far from the edge of the platform did the swimmer hit the water? Ignore wind resistance.A seagull flies at a velocity of 7.5 m/s relative to the air straight into the wind. vSA = 7.5 m/s t = 23 min d = 6.8 km If it takes the bird 23 min to travel 6.8 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive.
- Dwight decides to race around the perimeter of the Scranton business parkin an effort to beat another employee’s best running time. Assuming heruns with an average velocity of 10 ft/s, and he completes 4 laps in 5minutes,a. What is the perimeter of the business park in feet?b. In meters?( 1 ft = 0.3048 m )Mark and Karlos were betting on which among their marbles will reach the ground first after dropping them from the building's viewdeck 75 m high. However, Mark accidently drops his marble 1.4 seconds before the drop signal, causing Karlos's marble to drop last. At some time, if a spectator saw that the two marbles were 24 meters apart, how far from the bottom of the building was Karlos's marble at that instant? a. 29.4 m b. 45.6 m c. 52.5 m d. 69.6Please answer the following question(s): 1. The speed of a boat in still water is vá. A river flows with a speed of v₁. The boat travels distance of 19 miles downstream in a river in 1 hour. However, the return journey takes 2 hours. Calculate the vand v₁. Hint: Velocity=displacement/time. Displacement can be positive of neagtive depending on the direction. You will first need to set up the equations by taking into account the resultant velocity of the boat in flowing water. Consider the direction the river is flowing to be positive. Set up two equations, one for the downstream journey and one for the upstream journey, in terms of "v" and "v": Do v" and "v, add or substract downstream to give the resultant downstream velocity? Do v" and "v, add or substract upstream togive the resultant upstream velocity? Use the upstream direction as negative. The resultant upstream velocity should be negative. vb vb Downstream positive Vr Upstream negative Vr
- A ball is equipped with a speedometer and launched straight upward. The speedometer reading three seconds after launch is shown at the right; the ball is moving upward. At what approximate times would the ball display the following speedometer readings? ces_Pr....docx YAN e here to search LIC SCHOOLS 10 0 20 0 10 20 30 40 Speed m/s 50 5 Speed m/s 60 50 60 Bee_and_Bikes_Pr....docx 20 10 0 30 40 Speed m/s X 50 60 SEA cannon ball is launched into the air with an upward velocity of 294 feet per second, from a 10-foot tall cannon. The height hh of the cannon ball after tt seconds can be found using the equation h=−16t2+294t+10h=-16t2+294t+10. A) What was the initial height of the cannon ball? feet B) How many seconds will it take for the cannon ball to hit the ground? secondsIn a total time of 3.0 minutes, a duck on a pond paddles 31 m [N33oE] and then paddlesanother 57 m [E28oS]. Solve for the displacement graphically (with a ruler andprotractor) and then answer the questions. Using the displacement you determined from your graph, what was the duck’s average velocityfor the trip? What total distance did the duck travel? What was the average speed of the duck for the whole trip?