A 40.00 solution of 0.1430 M chloroacetic acid (pK a = 2.865) is titrated with a 0.1500 M solution of NaOH. a. Find the initial pH of the solution. b. Find the pH of the resulting solution at the half-equivalence point. c. Find the pH of the resulting solution at the equivalence point. d. Find the pH of the resulting solution at 0.50 mL past the equivalence point.
A 40.00 solution of 0.1430 M chloroacetic acid (pK a = 2.865) is titrated with a 0.1500 M solution of NaOH. a. Find the initial pH of the solution. b. Find the pH of the resulting solution at the half-equivalence point. c. Find the pH of the resulting solution at the equivalence point. d. Find the pH of the resulting solution at 0.50 mL past the equivalence point.
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 59E: Consider the titration of 100.0 mL of 0.200 M acetic acid (Ka = 1.8 105) by 0.100 M KOH. Calculate...
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A 40.00 solution of 0.1430 M chloroacetic acid (pK a = 2.865) is titrated with a 0.1500 M solution of NaOH.
a. Find the initial pH of the solution.
b. Find the pH of the resulting solution at the half-equivalence point.
c. Find the pH of the resulting solution at the equivalence point.
d. Find the pH of the resulting solution at 0.50 mL past the equivalence point.
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VIEWStep 2: determine initial pH of the solution
VIEWStep 3: determine pH of the resulting solution at the half-equivalence point
VIEWStep 4: determine pH of the resulting solution at the half-equivalence point.
VIEWStep 5: determine pH of the resulting solution at 0.50 mL past the equivalence point
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