The first picture is the question the second pic i did not understand that step of %75 of the load means what ? 7:41 4Step2b)Lse Know tuatThe efficiensy of the transfommerx x KVA x wsXI0Ox=0.75)kVA - 23Cos¢= 0-8664.VRm.r= (RLv) * Ev2,Rey. r =Co.o4)X ( 2300)Ru.v=42Resisteno refessed to primoy sideRp = R,t RH.VRp = 4+4Rp=8nStep3c)? A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage-reactance values: R1=40, R2=0.040, X1=120, and X2-0.120. The transformer is operating at 75%of its rated load. If the power factor of the load is 0.866 leading.Determine the efficiency of the transformer.

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A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage- reactance values: R1=40, R2=0.040, X1=120, and X2=0.12O. The transformer is operating at 75% of its rated load. If the power factor of the load is 0.866 leading. Determine the efficiency of the transformer.

A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage- reactance values: R1=40, R2=0.040, X1=120, and X2=0.12O. The transformer is operating at 75% of its rated load. If the power factor of the load is 0.866 leading. Determine the efficiency of the transformer.

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter4: Symbols

Section: Chapter Questions

Problem 7SQ: The symbol shown is a(n) a. iron core transformer. b. auto transformer. c. current transformer. d....

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The first picture is the question the second pic i did not understand that step of %75 of the load means what ?

7:41 4
Step2
b)
Lse Know tuat
The efficiensy of the transfommer
x x KVA x ws
XI0O
x=0.75)
kVA - 23
Cos¢= 0-866
4.V
Rm.r= (RLv) * Ev
2,
Rey. r =Co.o4)X ( 2300)
Ru.v=42
Resisteno refessed to primoy side
Rp = R,t RH.V
Rp = 4+4
Rp=8n
Step3
c)
?

A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage-
reactance values: R1=40, R2=0.040, X1=120, and X2-0.120. The transformer is operating at 75%
of its rated load. If the power factor of the load is 0.866 leading.
Determine the efficiency of the transformer.

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