A 2.00-kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20 x 10² N/m that is attached at the bottom of the incline. The coefficients of friction between the package and incline are µs = 0.400 and µk = 0.200. The mass of the spring is negligible. (a) What is the maximum compression of the spring? (b) The package rebounds up the incline. How does it get to its original position? (c) What is the change in the internal energy of the package and incline from the point at which the package is released until it rebounds to its maximum height? m = 2.00 kg/ D = 4.00 m %3D 0 = 53.1° %3D

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Chapter13: Vibrations And Waves
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A 2.00-kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant
1.20 × 10² N/m that is attached at the bottom of the incline. The coefficients of friction between
the package and incline are µs = 0.400 and µk = 0.200. The mass of the spring is negligible.
(a) What is the maximum compression of the spring?
(b) The package rebounds up the incline. How does it get to its original position?
(c) What is the change in the internal energy of the package and incline from the point at
which the package is released until it rebounds to its maximum height?
2.00 kg
m =
D = 4.00 m
e = 53.1°
Transcribed Image Text:A 2.00-kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20 × 10² N/m that is attached at the bottom of the incline. The coefficients of friction between the package and incline are µs = 0.400 and µk = 0.200. The mass of the spring is negligible. (a) What is the maximum compression of the spring? (b) The package rebounds up the incline. How does it get to its original position? (c) What is the change in the internal energy of the package and incline from the point at which the package is released until it rebounds to its maximum height? 2.00 kg m = D = 4.00 m e = 53.1°
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