A 10-9-F capacitor (1 nanofarad) is charged to 100 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 5x 1013 2; on a humid day, the resistance is 6x 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Use scientific notation. Round to three decimal places as needed.)

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter29: Direct Current (dc) Circuits
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Problem 72PQ: A capacitor with initial charge Q0 is connected across a resistor R at time t = 0. The separation...
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A 10-9-F capacitor (1 nanofarad) is charged to 100 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the
resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 5x 1013 2; on a humid day, the resistance is 6x 10° 2. How long will it take the
capacitor voltage to dissipate to half its original value on each day?
On the dry day, it will take seconds.
(Use scientific notation. Round to three decimal places as needed.)
Transcribed Image Text:A 10-9-F capacitor (1 nanofarad) is charged to 100 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 5x 1013 2; on a humid day, the resistance is 6x 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Use scientific notation. Round to three decimal places as needed.)
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