A1.42 g sample of KCr(SO)2 xH20 was heated in a crucible to get a constant mass. The mass of the produced anhydrous salt (KCr(SOh) (Molar mass = 283.1 g/mol) was 0.70 g.Calculate the value of 'x' in the formula. (Molar mass of H20 = 18.02 g/mol)O a 0.1Ob. 8Oc 10Od 15O e. 16Clear my choice

Formula to calculate mole is :- Mole = mass÷ molar mass

A 1.42 g sample of KCr(SO) XH20 was heated in a crucible to get a constant mass. The mass of the produced anhydrous salt (KCr(SO)2) (Molar mass = 283.1 g/mol) was 0.70 g. Calculate the value of 'x' in the formula. (Molar mass of H,O = 18.02 g/mol) O a 0.1 O b. 8 Oc 10 Od. 15 O e. 16 Clear my choice

A 1.42 g sample of KCr(SO) XH20 was heated in a crucible to get a constant mass. The mass of the produced anhydrous salt (KCr(SO)2) (Molar mass = 283.1 g/mol) was 0.70 g. Calculate the value of 'x' in the formula. (Molar mass of H,O = 18.02 g/mol) O a 0.1 O b. 8 Oc 10 Od. 15 O e. 16 Clear my choice

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter4: Stoichiometry

Section: Chapter Questions

Problem 4.87PAE

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

A1.42 g sample of KCr(SO)2 xH20 was heated in a crucible to get a constant mass. The mass of the produced anhydrous salt (KCr(SOh) (Molar mass = 283.1 g/mol) was 0.70 g.
Calculate the value of 'x' in the formula. (Molar mass of H20 = 18.02 g/mol)
O a 0.1
Ob. 8
Oc 10
Od 15
O e. 16
Clear my choice

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