A 1.27-cm diameter copper (r = 8933 kg/m3, C = 385 J/(kg °C)) sphere is heated in a convection furnace for a very long time so that its temperature becomes equal to the temperature of the air in the furnace at 260 °C. Then, the sphere is removed from the furnace and is placed in a forced convection flow where the heat transfer coefficient h is 17 W/(m2 °C) and where the temperature is 38 °C. If the thermal conductivity of copper is 400 W/(m °C) , calculate the Biot number.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter5: Analysis Of Convection Heat Transfer
Section: Chapter Questions
Problem 5.54P
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A 1.27-cm diameter copper (r = 8933
kg/m3, C = 385 J/(kg °C)) sphere is heated
in a convection furnace for a very long time
so that its temperature becomes equal to
the temperature of the air in the furnace at
260 °C. Then, the sphere is removed from
the furnace and is placed in a forced
convection flow where the heat transfer
coefficient h is 17 W/(m2 °C) and where
the temperature is 38 °C. If the thermal
conductivity of copper is 400 W/(m °C) ,
calculate the Biot number.
4.25x10^-5
8.5x10^-5
1.7x10^-4
O 3.4×10^-4
Transcribed Image Text:A 1.27-cm diameter copper (r = 8933 kg/m3, C = 385 J/(kg °C)) sphere is heated in a convection furnace for a very long time so that its temperature becomes equal to the temperature of the air in the furnace at 260 °C. Then, the sphere is removed from the furnace and is placed in a forced convection flow where the heat transfer coefficient h is 17 W/(m2 °C) and where the temperature is 38 °C. If the thermal conductivity of copper is 400 W/(m °C) , calculate the Biot number. 4.25x10^-5 8.5x10^-5 1.7x10^-4 O 3.4×10^-4
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