A 0.065 kg of ice cube at 0°C is placed in 0.835kg of water at 28°C. What is the final equilibrium temperature of the mixture? Given specific heat of ice =0.5 cal/g°C and specific heat of water=1 cal/g°C (3 mark)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
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Chapter19: Temperature
Section: Chapter Questions
Problem 19.5OQ: A temperature of 162F is equivalent to what temperature in kelvins? (a) 373 K (b) 288 K (c) 345 K...
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A 0.065 kg of ice cube at 0°C is placed in 0.835kg of water at 28°C. What is the final equilibrium temperature
of the mixture? Given specific heat of ice =0.5 cal/g°C and specific heat of water=1 cal/goC
(3 mark)
Transcribed Image Text:A 0.065 kg of ice cube at 0°C is placed in 0.835kg of water at 28°C. What is the final equilibrium temperature of the mixture? Given specific heat of ice =0.5 cal/g°C and specific heat of water=1 cal/goC (3 mark)
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