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- √1-1.x² 9. Convert ¹, (4-4x²-y²) dyda into a triple integral with dV = dydzdx. √1-1²Edit Evaluate the integral / (2x + 12y)dx + (24x – y)dy along the parabolic arc y = x from (0,0) to (1,1). NOTE: Enter the exact answer. (2х + 12y)dx + (24х — у) dy9. Evaluate the integral ex V2e-2x – 3e2x 2/2e-2x – 3e2x +C А. 1 3eªx – 2+C B. 2/3 Arcan V3e2x Arcsin 1 +C C. V3 -Arcsin 6. +C D.