Common data for Q. 7 and Q. 8.Consider two concentric conducting spherical shells with inner and outer radii a, b and c, d as shown inthe figure. Both the shells are given Q amount of positive charges.7.The electric field in different regions are(a) E= 0 for rdCAREER ENDEAVOUR.(b) E= î for rd(c) E =-,i for r a; = 0 for a dIn order to have equal surface charge densities on the outer surfaces of both the shells, the followingconditions should be satisfied8.(b) d= 2b and c = 2a(d) d> b and c = 2a(a) d = 4b and c = 2a(c) d = /2b and e>a

Given: Two conducting shell of inner and outer radius is given a charge Q.

8. In order to have equal surface charge densities on the outer surfaces of both the shells, the following conditions should be satisfied (b) d= 2b and e = /2a (d) d> b and e = 2a (a) d = 4b and e = 2a (c) d = /2b and e >a

8. In order to have equal surface charge densities on the outer surfaces of both the shells, the following conditions should be satisfied (b) d= 2b and e = /2a (d) d> b and e = 2a (a) d = 4b and e = 2a (c) d = /2b and e >a

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 94P: A proton enters the uniform electric field produced by the two charged plates shown below. The...

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Question

Common data for Q. 7 and Q. 8.
Consider two concentric conducting spherical shells with inner and outer radii a, b and c, d as shown in
the figure. Both the shells are given Q amount of positive charges.
7.
The electric field in different regions are
(a) E= 0 for r<a; E =-i for a <r<b; E=0 for b<r<c;E
4TE,
zf for r>d
CAREER ENDEAVOUR.
(b) E= î for r<a; E0 for ar<b; 4TEr
for bre; E=-
-î for r<d
Ē= 0b<r<c;Ë =-
20
-î for r>d
(c) E =-,i for r<a; E = 0 for a < r<b;
4περ
2Q
(d) Ē = 0 for r> a; = 0 for a <r<b; Ē=-
gf for b <r<c; =-
4TE,r²
î for r>d
In order to have equal surface charge densities on the outer surfaces of both the shells, the following
conditions should be satisfied
8.
(b) d= 2b and c = 2a
(d) d> b and c = 2a
(a) d = 4b and c = 2a
(c) d = /2b and e>a

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