77. For the reaction SbCls(g) AG (SbCls)=-334.34 kJ/mol SbCl3(g) + Cl2(g), AG°f (SbC13)=-301.25 kJ/mol AH (SbCls)=-394.34 kJ/mol AH°(SbC13)=-313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure. A. 1.31 x 103 B. 1.11 x 103 C. 1.91 x 102 D. 1.71 x 102 E. None of the above

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 22PS: For the reaction TiCl2(s) + Cl2(g) TiCl4(), rG = 272.8 kj/mol-txn. Using this value and other data...
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77. For the reaction SbCls(g)
AG (SbCls)=-334.34 kJ/mol
SbCl3(g) + Cl2(g),
AG°f (SbC13)=-301.25 kJ/mol
AH (SbCls)=-394.34 kJ/mol
AH°(SbC13)=-313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure.
A. 1.31 x 103
B. 1.11 x 103
C. 1.91 x 102
D. 1.71 x 102
E. None of the above
Transcribed Image Text:77. For the reaction SbCls(g) AG (SbCls)=-334.34 kJ/mol SbCl3(g) + Cl2(g), AG°f (SbC13)=-301.25 kJ/mol AH (SbCls)=-394.34 kJ/mol AH°(SbC13)=-313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure. A. 1.31 x 103 B. 1.11 x 103 C. 1.91 x 102 D. 1.71 x 102 E. None of the above
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