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75% of all deaths in the United States are attributed to just 10 causes, with the top four of these accounting for ov 50% of all non-accidental deaths as follows: heart disease (23.4%), cancer (22.5%), respiratory disease (5.6%), and stro 5.1%). A study of the causes of n = 303 non-accidental deaths at a local hospital gave the following counts. Cause Heart Disease Deaths 79 Cancer 80 = Do the data provide sufficient information to indicate that the number of deaths at this hospital differ significantly from the roportions in the population at large? Test using the p-value approach. (Use a = 0.05.) 1 O Ho: P₁ = P₂ = P3 = P4 = P5 = 5 H: At least one p, is different from O Ho: At least one p, is different from tate the null and alternative hypotheses. O Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P = 0.434 H₂: At least one p, is different from the specified value. Ha: P₁ P₂ P3 = P4 = P5 Respiratory Disease 27 OH: At least one p, is different from the specified value. Ha: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P = 0.434 0.005 p-value < 0.010 0.010 p-value < 0.025 1 == at can be said about the p-value? Op-value < 0.005 Stroke Other 14 103 13/ 5 O Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P = 0.434 H₂: No value of p, is the same as its specified value. d the test statistic. (Round your answer to two decimal places.)

75% of all deaths in the United States are attributed to just 10 causes, with the top four of these accounting for ov 50% of all non-accidental deaths as follows: heart disease (23.4%), cancer (22.5%), respiratory disease (5.6%), and stro 5.1%). A study of the causes of n = 303 non-accidental deaths at a local hospital gave the following counts. Cause Heart Disease Deaths 79 Cancer 80 = Do the data provide sufficient information to indicate that the number of deaths at this hospital differ significantly from the roportions in the population at large? Test using the p-value approach. (Use a = 0.05.) 1 O Ho: P₁ = P₂ = P3 = P4 = P5 = 5 H: At least one p, is different from O Ho: At least one p, is different from tate the null and alternative hypotheses. O Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P = 0.434 H₂: At least one p, is different from the specified value. Ha: P₁ P₂ P3 = P4 = P5 Respiratory Disease 27 OH: At least one p, is different from the specified value. Ha: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P = 0.434 0.005 p-value < 0.010 0.010 p-value < 0.025 1 == at can be said about the p-value? Op-value < 0.005 Stroke Other 14 103 13/ 5 O Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P = 0.434 H₂: No value of p, is the same as its specified value. d the test statistic. (Round your answer to two decimal places.)

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter12: Probability
Section12.3: Conditional Probability; Independent Events; Bayes' Theorem
Problem 82E
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... ***************** Nearly 75% of all deaths in the United States are attributed to just 10 causes, with the top four of these accounting for ove 50% of all non-accidental deaths as follows: heart disease (23.4%), cancer (22.5%), respiratory disease (5.6%), and strok (5.1%). A study of the causes of n = 303 non-accidental deaths at a local hospital gave the following counts. Cause Heart Disease Deaths 79 Cancer 80 Respiratory Disease 27 Do the data provide sufficient information to indicate that the number of deaths at this hospital differ significantly from the proportions in the population at large? Test using the p-value approach. (Use α = 0.05.) 1 O Ho: At least one p, is different from 5 1 Ha: P1 P2 P3 = P4 = P5 = 5 0.005 p-value < 0.010 0.010 p-value < 0.025 0.025 p-value < 0.050 0.050 < p-value < 0.100 O p-value> 0.100 Stroke Other State the null and alternative hypotheses. O Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; p = 0.051; P5 = 0.434 H: At least one p, is different from the specified value. What can be said about the p-value? O p-value < 0.005 14 O Ho: At least one p, is different from the specified value. H₂: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P5 = 0.434 O Ho: P₁ = P₂ = P3 P4 P5 = = = 1 Ha: At least one p, is different from 5 103 Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P5 = 0.434 H: No value of p, is the same as its specified value. Find the test statistic. (Round your answer to two decimal places.) x² = State your conclusion. O Since the p-value is greater than 0.05, Ho is not rejected. There is insufficient evidence to conclude that the proportio of non-accidental deaths from certain diseases at this hospital differ from the proportions for the larger population. O Since the p-value is less than 0.05, Ho is rejected. There is sufficient evidence to conclude that the proportions of non accidental deaths from certain diseases at this hospital differ from the proportions for the larger population. O Since the p-value is less than 0.05, Ho is not rejected. There is sufficient evidence to conclude that the proportions of non-accidental deaths from certain diseases at this hospital differ from the proportions for the larger population. O Since the p-value is greater than 0.05, Ho is rejected. There is insufficient evidence to conclude that the proportions o non-accidental deaths from certain diseases at this hospital differ from the proportions for the larger population.
Transcribed Image Text:... ***************** Nearly 75% of all deaths in the United States are attributed to just 10 causes, with the top four of these accounting for ove 50% of all non-accidental deaths as follows: heart disease (23.4%), cancer (22.5%), respiratory disease (5.6%), and strok (5.1%). A study of the causes of n = 303 non-accidental deaths at a local hospital gave the following counts. Cause Heart Disease Deaths 79 Cancer 80 Respiratory Disease 27 Do the data provide sufficient information to indicate that the number of deaths at this hospital differ significantly from the proportions in the population at large? Test using the p-value approach. (Use α = 0.05.) 1 O Ho: At least one p, is different from 5 1 Ha: P1 P2 P3 = P4 = P5 = 5 0.005 p-value < 0.010 0.010 p-value < 0.025 0.025 p-value < 0.050 0.050 < p-value < 0.100 O p-value> 0.100 Stroke Other State the null and alternative hypotheses. O Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; p = 0.051; P5 = 0.434 H: At least one p, is different from the specified value. What can be said about the p-value? O p-value < 0.005 14 O Ho: At least one p, is different from the specified value. H₂: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P5 = 0.434 O Ho: P₁ = P₂ = P3 P4 P5 = = = 1 Ha: At least one p, is different from 5 103 Ho: P₁ = 0.234; P₂ = 0.225; P3 = 0.056; P4 = 0.051; P5 = 0.434 H: No value of p, is the same as its specified value. Find the test statistic. (Round your answer to two decimal places.) x² = State your conclusion. O Since the p-value is greater than 0.05, Ho is not rejected. There is insufficient evidence to conclude that the proportio of non-accidental deaths from certain diseases at this hospital differ from the proportions for the larger population. O Since the p-value is less than 0.05, Ho is rejected. There is sufficient evidence to conclude that the proportions of non accidental deaths from certain diseases at this hospital differ from the proportions for the larger population. O Since the p-value is less than 0.05, Ho is not rejected. There is sufficient evidence to conclude that the proportions of non-accidental deaths from certain diseases at this hospital differ from the proportions for the larger population. O Since the p-value is greater than 0.05, Ho is rejected. There is insufficient evidence to conclude that the proportions o non-accidental deaths from certain diseases at this hospital differ from the proportions for the larger population.
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