7- Calculate the capacitance (in pF) of a parallel-plate capacitor navinng a dielectric of e, = 4, %3D a plate area of 80 cm?, and a separation of 2 cm. (h) 10 6 (a) 14 2 (c) 23.6 (d) 17.7
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- A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?(6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of 2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the capacitance of the system. Note: for parallel slabs; Conductor 1 E = T 1 Air E1 83 Material A Material 3 Conductor Ans. C = 54 pF1.3 A coaxial cylindrical capacitor is to be designed with an effective length of 10 cm. The capacitor is expected to have a capacitance of 100 pF and to operate at 11 kV, 1000 kHz. Determine the required thickness if the required insulating material is Polytetrafluoroethylene (P.T.F.E.), &r= 2.0, Eb = 250 kV/cm. Allow a factor of safety of 4 and take to = 8.85x10-1² F/m.
- A spherical capacitor have an inner radius of 38.5 mm and an outer radius of 41.6 mm. If we want to replace it with a parallel plate capacitor of the same capacitance and seperation distance, what should the area of each plate be? A) 223.2 cm² B) 219.5 cm² 215.8 cm² D) 212.1 cm² E 208.5 cm² F 204.9 cm² G) 201.3 cm² H) 197.7 cm² None of the above.Research and explain the following topics and cite examples oneach topics 1.) Capacitance of a Two parallel-plate capacitor with uniform dielectric medium.2.) Capacitance of an “n” parallel-plate capacitor having the same type of dielectric material and thickness of dielectric uniform dielectric medium.3.) Capacitance of an “n” parallel-plate capacitor having the different dielectric material and thickness of dielectric uniform dielectric medium.4.) Capacitance of a Two parallel-plate capacitor with a medium partly air.5.) Capacitance of a coaxial cable (Farad per meter).If this were actually a parallel plate capacitor, which would be the dielectric constant of the dielectric? assume the capacitor has plate that are 2.50 mm by 2.25 mm, and the plates are separated by a distance of 3.30 mm.
- 3. Two circular metal plates of radius 0.610 m and thickness 7.10 mm are used in a parallel plate capacitor. A gap of 2.10 mm is left between the plates, and half of the space ( a semicircle) between them is filled with a dielectric for which k=11.1 and the other half is filled with air. What is the capacitance of this capacitor?If the voltage on a capacitor decreases to (4/5) of its initial value when a dielectric material is settled in it what is the dielectric constant of that material (Eo-8.8542 x 10-¹2 C/Vm) ? IPlease answer quickly The angular frequency of waveform having a period of 1 msec is 2pi radians/sec. True False Root mode square value of a signal is same as the effective value of a signal. True False The magnetic field energy stored in between the plates of the capacitor is mathematically equal to the half of the product of its capacitance and the square of the voltage across the capacitor. True False
- Capacitors. Can you explain please why this is .50x10^(-13)?Suppose a capacitor is made using square plates that are 5.1 cm on a side, and are separated by 5.2 mm. If a dielectric is inserted between the plates as well, with a dielectric constant of 8.7, what is the capacitance of the capacitor? Enter your answer in pF (10-12 F) to two decimal places and without units. Answer:Find the capacitance (in pF) of parallel-plate capacitor containing two dielectrics with ert = 1.5 and er2 = 3.5, each comprising one-half the volume. The area of the plates is 20 cm2 and the distance between them is 1 cm. O 6.64 O 4.43 O 7.30 5.81