6. The gene for normal vision is dominant and sex linked (XB). The gene for red-green color-blindness is recessive and sex linked (Xb). a. Draw a Punnett Square and then give the genotypic and phenotypic ratios of the offspring wh a carrier female marries a color-blind male. Woman III-4 III-5 Offspring Genotype Ratio Phenotype Ratio X Man Punnett Square

6. The gene for normal vision is dominant and sex linked (XB). The gene for red-green color-blindness is recessive and sex linked (Xb). a. Draw a Punnett Square and then give the genotypic and phenotypic ratios of the offspring wh a carrier female marries a color-blind male. Woman III-4 III-5 Offspring Genotype Ratio Phenotype Ratio X Man Punnett Square

Name: Step by step 6. The gene for normal vision is dominant and sex linked
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Description: Step by step 6. The gene for normal vision is dominant and sex linked (XB).The gene for red-green color-blindness is recessive and sex linked (Xb).a.Draw a Punnett Square and then give the genotypic and phenotypic ratios of the offspring whena carrie

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 1SQ: A heterozygous individual has a _______ for a trait being studied. a. pair of identical alleles b....

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2.) (6) Assume that brown eyes are dominant = B, blue eyes are recessive = b. My first wife has blues eyes. I know I am homozygous dominant a. What is her genotype? b. What are her possible gamete genotypes? c. What is my genotype? d. What are my possible gamete genotypes? What genotype(s) do you expect of our offspring? Show your work (Punnett square is a good idea). e.
1. Hemophilia is a disease inherited as a X-linked recessive trait while pattern baldness is controlled by an autosomal gene that is dominant in males and recessive in females. A hemophilic man who is also homozygous for baldness has children with a woman who is not hemophilic but a carrier and heterozygous normal-haired. Show the parental genotypes, the Genotypic ratio (GR) of the offspring and their phenotypic ratio. Separate the total number of the male offspring from female offspring. For example, if there are 8 total number of offspring, count how many are females and how many are males. So if there are 4 females, then the denominator for the genotypic ratio and phenotypic ratio for female offspring is 4. You can convert it to percentage if you want. Answer the following: a. Among the female offspring, what is the probability of having hemophilic but normal haired child? b. Among the male offspring, what is the chance of having a child with normal blood clotting but bald?
1. In "Four o' Clock “plants, it's flower color is incompletely dominant. The red flowers are homozygous dominant, the white flowers are homozygous recessive, and the pink flowers are heterozygous. Show genetic crosses between the following Four O'clock parents, using the Punnett squares provided and indicate the genotypic and phenotypic % below: A. Red x white Genotypic %: Phenotypic %: B. White x Pink Genotypic %: Phenotypic %: C. Pink x Pink Genotypic %: Phenotypic %:
1. If one parent is homozygous dominant for a trait, that parent's genotype might be GG. If the other parent is homozygous recessive for the same trait, that parent's genotype would be gg. What are the possible genotypes of their offspring? b. How many different phenotypes might we possibly see in their offspring? 2. If a male is homozygous dominant for a trait, that parent's genotype might be DD. If the female is heterozygous for the same trait, her genotype would be Dd. a. How many genetically different sperm can the male produce? b. Using a Punnett square, determine the expected genotypic ratios of their offspring. What are the expected phenotypic ratios? 3. In garden peas, the gene for red flowers (R) is dominant over the gene for white flowers (r). If pollen (cells containing sperm nuclei) from the anther (male reproductive organ) of a homozygous red-flowered plant is added to the pistil (female reproductive organ containing the egg) of a white- flowered plant: a. c. What would be…
9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.
1. Complete the Punnett square for a cross between a homozygous red-flowered snapdragon (RR) and a homozygous white-flowered snapdragon (WW). Give the ratio for the phenotype and the genotype. Key F1 Genotypic Ratio: RR – red Phenotypic Ratio: wW- white RW- pink 2. Complete the Punnett Square for a cross between two Fi plants (WW). Give the phenotypic ratio for the F2 generation. F2 Phenotypic ratio: 3. Cite some possible applications of genetics to plant breeding.
1. Muscular dystrophy is an x linked recessive disorder. If two of the four offsprings have muscular dystrophy and the other two are normal, predict the genotype of the parents. The offsprins are all boys and the parents appear normal. 2. At age 50, the girl is bald and the boy is not bald. They are twins. What is the genotype of the girl? Predict the genotype of the parents of the twins.
1. Windows peak (S) is dominant over straight hairline (s). Given that the mother has heterozygous gene pair for window's peak and the father has straight hairline. a. What is the genotype of the mother? b. What is the genotype of the father? * How many kinds of gametes can the mother produce? List them down. d. How many kinds of gametes can the father produce? List them down. e. Perform a cross using a Punnett square. f. Give the genotypic ratio of the cross g. Give the phenotypic ratio of the cross A 4.
2. Can a color-blind female have a son that has normal vision? Color blindness is caused by a sex-linked recessive allele. Explain. Do the Punnett square. *use N = normal vision and n = color blind over X and Y chromosomes. 3. Muscular dystrophy is a sex-linked trait. What parental genotypes could produce a female with=muscular dystrophy? Do the Punnett square. *use M = normal muscles, and m = muscles missing dystrophin protein over X and Y chromosomes. 4. In humans, red-green color-blindness is due to a recessive gene X^c. Normal vision results from the dominant gene X^c. If a homozygous woman of normal vision marries a color-blind man, what type of vision will be expected in their children?
Brown eyes are dominant over blue. This is NOTA sex-linked trait. If a blue-eyed colorblind woman marries a normal visioned man who is homozygous for brown eye color, what kind of children might they expect with respect to these two traits? 5. Genotype of woman _Genotype of man What two genotypes are possible in the children? If one of the sons in turn marries a heterozygous brown-eyed, normal visioned woman, not a carrier, what kinds of children might they expect? Genotypes Phenotypes
1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
1. A woman is colorblind. Construct a Punnett square and using versions of the letter “C” determine if she marries a man with normal vision: What are the chances her sons will be colorblind? What are the chances her daughters will be colorblind? What are the chances of having a carrier daughter? 2. Both the husband and wife have normal vision. Their son is colorblind. What can you conclude about the father’s genotype? What about the mother’s genotype? Father: Mother: 3. If a young girl has fragile X syndrome, a recessive trait (f), what is her genotype? What are the possible genotypes of her father and mother? Mother: _________ or __________ Father: _________________ If her brother also developed this condition, which parent (father, mother, or both) contributed a disease allele? Explain your answer as well as constructing Punnett squares to support your answer. 4. Both the mother and father of a hemophiliac son have normal blood clotting. What are the genotypes of the…