566 For each of the other 3 modes of inheritance, briefly explain why it is not possible (or not the most probable ive individuals in the pedigree as evidence (use the I-2 form for designating them).
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- A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?A heterozygous individual has a _______ for a trait being studied. a. pair of identical alleles b. pair of nonidentical alleles c. haploid condition, in genetic terms
- 1. In the pedigree below, Use "A" for the allele associated with the dominant phenotype, and lowercase "a" for the allele associated with the recessive phenotype. Determine what is the most likely mode of inheritance of this disease (whether it is inherited as the result of an autosomal dominant or autosomal recessive trait). Write the most probable genotype for each individual based on the mode of inheritance you have determined. Show how all the partners are crossed and the expected offspring produced (You may use Punnett Square) 1 dró || IV9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.26. The trait represented in the following pedigree is expressed only in the males of the family. Is the trait Y linked? Why or why not? If you believe that the trait is not Y linked, propose an alternative explanation for its inheritance. 1 2 II 3 6 II I 2 3 4 5 6 7 8 IV 1 2 Pierce, Genetics: A Conceptual Approach, 7e © 2020 W. H. Freeman and Company
- 11. What evidence do you see in the pedigree illustrated if any, allowing the mode of inheritance for this trait to be deduced as completely vs. incompletely dominant? Do not consider any other information beyond what is shown in the pedigree. Answer in one complete sentence, referring to any individuals in the pedigree who may be informative using generation and individual numbers.3) The most likely inheritance pattern in the pedigree above is:BIU A- == 三E 12 - Match each of the following examples to the appropriate type of non-Mendelian inheritance. 1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower.color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers,…
- A. What is the inheritance pattern of the pedigree illustrated above? Explain in 1 sentence minimum citing two pieces of evidence from the pedigree to support your answer. B. Assuming that the disorder portrayed in this pedigree is very rare, based on your answer in a., what are the most likely genotypes of I-2, Ill-7 and I1-3. C. Based on your answer in a, what are the odds that IV-1 and IV-2 would have an affected male child?6) For the pedigree shown below, answer the following questions. I II III a) What type of inheritance is shown? Explain how you know. b) The genotype of individual I -2 is The genotype of individual II -1 is6. The pedigree below traces the inheritance of a particular disorder. Circles are females, squares are males. Shaded symbols are affected with the disorder (NOTE: "half-shaded" symbols are NOT used here, for heterozygous individuals). What is the mode of inheritance of this disorder: is it dominant or recessive? Autosomal or X-linked? What is the genotype of the three numbered individuals? 1 2. 3.