5.70 nÇ is moving in a uniform A particle with charge magnetic field B = -( 1.23 T )k. The magnetic force on the no particle is measured to be F = -( 3.70x10-7 N )î+(7.60×10-7 N )§. Submit Previous Answers v Correct Part B Calculate the x-component of the velocity of the particle. Express your answer in meters per second. ? m/s Submit Request Answer Part C Calculate the y-component of the velocity of the particle. Express your answer in meters per second. ? Vy = m/s Submit Request Answer

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter11: Magnetic Forces And Fields
Section: Chapter Questions
Problem 48P: A strip of copper is placed in a uniform magnetic field of magnitude 2.5 T. The Hall electric field...
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A particle with charge – 5.70 nC is moving in a uniform
magnetic field B=-(1.23 T )k. The magnetic force on the
particle is measured to be
F = -( 3.70x10-7 N )î+(7.60×10-7 N )ĝ.
O no
Submit
Previous Answers
Correct
Part B
Calculate the x-component of the velocity of the particle.
Express your answer in meters per second.
?
Vr =
m/s
Submit
Request Answer
Part C
Calculate the y-component of the velocity of the particle.
Express your answer in meters per second.
Vα ΑΣφ
?
Vy =
m/s
%3D
Submit
Request Answer
Transcribed Image Text:A particle with charge – 5.70 nC is moving in a uniform magnetic field B=-(1.23 T )k. The magnetic force on the particle is measured to be F = -( 3.70x10-7 N )î+(7.60×10-7 N )ĝ. O no Submit Previous Answers Correct Part B Calculate the x-component of the velocity of the particle. Express your answer in meters per second. ? Vr = m/s Submit Request Answer Part C Calculate the y-component of the velocity of the particle. Express your answer in meters per second. Vα ΑΣφ ? Vy = m/s %3D Submit Request Answer
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