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5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 7.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2*] was found to be 2.00 x 104 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN¯ (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 7.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2*] was found to be 2.00 x 104 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN¯ (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter20: Chemistry Of The Metals
Section: Chapter Questions
Problem 42QAP: Rust, which you can take to be Fe(OH)3, can be dissolved by treating it with oxalic acid. An...
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5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power MF (NO3)3) is added to 7.00 mL of 5.00 x 103 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 104 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents). Your Answer: Answer units
Transcribed Image Text:5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power MF (NO3)3) is added to 7.00 mL of 5.00 x 103 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 104 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents). Your Answer: Answer units
Expert Solution
Step 1

Given: Concentration of Fe(NO3)3 taken = 5.00 × 10-3 M

Volume of Fe(NO3)3 solution taken = 5.00 mL 

Concentration of KSCN taken = 5.00 × 10-3 M

Volume of KSCN solution taken = 7.00 mL.

The volume of water added = 5.00 mL.

And the equilibrium concentration of Fe(SCN)2+ = 2.00 × 10-4 M

 

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