5. Write the three-address code for the following program snippet: i=1; x = 0; n = 20; while (i <= n) { } x= x + 1; i=i+1;
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- 7. Translate the following function into pseudo-assembly: Void swap_nums(int a, int b){ if (a b) return a; 3 int temp = 0; temp = a; a = b; b temp;#include using namespace std; bool isPalindrome(int x) { int n=0,val; val = x; while(x > 0) { n = n * 10 + x % 10; x = x / 10; } } int main() { int n; cin >>n; if(isPalindrome(n)) { cout <CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
- Assignment for Computer Architecture: N Factual by Recusion *please have comments in the code* You are to write a program in MIPS that computes N! using recursion. Remember N! is the product of all the numbers from 1 to N inclusive, that is 1 x 2 x 3 x (N – 1) x N. It is defined as 1 for N = 0 and is undefined for values less than 0. The programs first requests the user to input the value of N (display a prompt first so the user knows what to do). If the input value is less than 0, the program is to display “N! undefined for values less than 0” and then requests the user to input the value of N again. If the value input is non-negative, it is to compute N! using a recursive function, that is one that calls itself. You are to have your name, the assignment number, and a brief description of the program in comments at the top of your program. Since this is an assembly language program, I expect to see comments on almost every line of code in the program. Also make the…Language: JAVA Problem 1: Decimal to Binary Conversion Write a program that takes an integer value as an input and converts that value to its binary representation; for instance, if the user inputs 17, then the output will be 10001. Do not forget to check for valid input, which means if the user inputs a type of data other than an integer re-prompt the user to enter a valid value. The output binary number can be a string. Sample input and output: Enter an integer > a You entered an invalid type. Try again. Enter an integer > 17 10001Code write () 9.
- 1、Counting Primitive Operations void STRAITMAXMIN(A,n,max,min) //Set the maximum value in A to max and the minimum value to min { int i,n max=min=A[1] for i=2 to n { if A[i]> max max=A[i]; if A[i]< min min=A[i]; } }3. Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in the following skeletal program. Assume bigsub is at level 1. function bigsub() { function a(flag) { function b() { *** a(false); } // end of b *** *** if (flag) b(); else c(); } // end of a function c() { function d() { <--- *** } // end of d d(); } // end of c *** 2 a(true); } // end of bigsub The calling sequence for this program for execution to reach dis bigsub calls a a calls b 12The code box below defines a variable route as a list of directions to navigate a maze. Each instruction is one of the following four basic commands: • higher. move one step in the positive y direction • lower: move one step in the negative y direction • left: move one step in the negative x direction right: move one step in the positive x direction ● Define a function move that takes two arguments, a location (as a tuple of x and y coordinates) and an instruction (higher, lower, left, right) as a string. Given the provided location, it should return the new location (as a tuple of x and y coordinates) when following the specified instruction. If the instruction is invalid, the old location should be returned. Use the function move to determine the final position when starting from the point (-2, -1) and following all instructions in the list route. Assign this final position to the variable final_location. Reset answer 1 route = ['right', 'higher', 'left', 'lower', 'higher', 'left',…
- 6. //Program 4.6 #include #include int main (){ char c1, c2, с3, с4; cl=65; c2='A'; c3=0x41; c4=0101; printf("%c %d %f %s", c1, c2, c3, c4); getch(); return 0; H N M 4567 o OProgramming Language: Python 4. Write a Python function that will take a positive integer n from the user as an argument and returns the largest power of two greater than or equal to n.#include<bits/stdc++.h>#include<math.h>using namespace std; class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in…